Answer:
x = -25/13
Step-by-step explanation:
Subtract 41 from 16 and divide the difference by 13
Answer:
See below
Step-by-step explanation:
Part A
<em><u>Formula</u></em>
M = 2/3 * log(E/Eo)
<em><u>Givens</u></em>
M = ??
E = 2 * 10^15 joules
Eo = 10^4.4
<em><u>Solution</u></em>
M = (2/3) * log(2 * 10^15 / 10^4.4)
M = (2/3 ) log (7.96 * 10 ^ 11)
M = (2/3) * 11.901
M = 7.934
Part B
What the question is saying is that E/Eo = 10000
You don't have to figure out exact values.
M = 2/3 * log(10000)
M = 2/3 * 4
M = 8/3 or 2 2/3 or 2.66667
If you have choices, please list them.
To compare fractions, we need to have the same denominator
The least common multiple is
16
to change

, we should multiply the numerator and denominator by
4

=


<

so basically,

is greater than

which means

is greater

is greater
Answer:
B
Step-by-step explanation:
no sales tax is added to butter per the chart.
To solve this problem, you have to know these two special factorizations:

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:
![\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%2Bh%7D%3Dx%5C%5C%20%5Csqrt%5B3%5D%7Bx%7D%3Dy%20)
That tells us that we have:

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

So, we have:
![\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2Bh-h%7D%7Bh%28%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7B%28x%2Bh%29%28x%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%29%7D%3D%5C%5C%20%5Cfrac%7Bx%7D%7B%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7B%28x%2Bh%29%28x%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%7D%20)
That is our rational expression with a rationalized numerator.
Also, you could just mutiply by:
![\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx_h%7D-%5Csqrt%5B3%5D%7Bx%7D%7D%20%5Ctext%7B%20to%20get%7D%5C%5C%20%5Cfrac%7B1%7D%7Bh%5Csqrt%5B3%5D%7Bx%2Bh%7D-h%5Csqrt%5B3%5D%7Bh%7D%7D%20)
Either way, our expression is rationalized.