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My name is Ann [436]

2 years ago

9

alaska's glacier bay national had 431, 986 visitors in one year the next year the part had 22,351 more visitors than a year befo

re how many people visited during the two years

1 answer:

PIT_PIT [208]2 years ago

5 0

22,351 + 431,986 = <span>454,337

454,337 + 431,986 = </span><span>886,323

during the two years </span><span>886323 people visited </span>

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Solve equation.<br> 13x + 41 = 16

sveta [45]

Answer:

x = -25/13

Step-by-step explanation:

Subtract 41 from 16 and divide the difference by 13

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2 years ago

Read 2 more answers

On the Richter scale, the magnitude, M, of an earthquake is given by M= 2/3logE/Eo, where E is the energy released by the earthq

Ivahew [28]

Answer:

See below

Step-by-step explanation:

Part A

<em><u>Formula</u></em>

M = 2/3 * log(E/Eo)

<em><u>Givens</u></em>

M = ??

E = 2 * 10^15 joules

Eo = 10^4.4

<em><u>Solution</u></em>

M = (2/3) * log(2 * 10^15 / 10^4.4)

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M = (2/3) * 11.901

M = 7.934

Part B

What the question is saying is that E/Eo = 10000

You don't have to figure out exact values.

M = 2/3 * log(10000)

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M = 8/3 or 2 2/3 or 2.66667

If you have choices, please list them.

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2 years ago

Which is greater 11/16 or 3/4

Anettt [7]

To compare fractions, we need to have the same denominator
The least common multiple is 16
$\frac{11}{16}$
to change $\frac{3}{4}$ , we should multiply the numerator and denominator by 4
$\frac{3*4}{4*4}$ = $\frac{12}{16}$

$\frac{11}{16}$ < $\frac{12}{16}$

so basically, $\frac{12}{16}$ is greater than $\frac{11}{16}$
which means $\frac{3}{4}$ is greater

$\frac{3}{4}$ is greater

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2 years ago

Please help me!!!! I’ll mark you as brainliest!!!!!!!

Nataliya [291]

Answer:

B

Step-by-step explanation:

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3 years ago

How do you rationalize the numerator in this problem?

maw [93]

To solve this problem, you have to know these two special factorizations:

$x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)$

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

$\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y$

That tells us that we have:

$\frac{x-y}{h}$

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

$\frac{x-y}{h}*\frac{x^2+xy+y^2}{x^2+xy+y^2}=\frac{x^3-y^3}{h*(x^2+xy+y^2)}$

So, we have:

$\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}$

That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

$\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}$

Either way, our expression is rationalized.

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3 years ago