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krok68 [10]
3 years ago
12

Which expression represents the product of 25 and 9 divided by 5?

Mathematics
2 answers:
Mademuasel [1]3 years ago
5 0

Answer:

25+9÷5

Step-by-step explanation:

Nat2105 [25]3 years ago
3 0

"The product of" means multiplication, so the equation will be:

(25 × 9) ÷ 5

or

(25 × 9)/5

Also, not sure if you need it, but to find the answer solve the equation in the parenthesis first.

25 × 9 = 225

Now we have 225 ÷ 5. Divide to solve.

225 ÷ 5 = 45

I hope this helps :)

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Helen [10]
.781111111 repeating. or 43/55
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3 years ago
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Jeremy mowed serval lawns to earn money for his camp after he paid 17$ for gas , he had 75$ leftover to play towards camp. write
mart [117]
So Jeremy had x amount of  money to begin with
he then spent $17 and was left with $75 to spend for camp so
x-17=75
add 17 to both sides
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3 0
3 years ago
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When an amount of heat Q (in kcal) is added to a unit mass (kg) of a
lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71.\overline {6} °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)

\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)

Therefore, we get;

\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}

\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C }   = 71.\overline 6 \, ^{\circ } C/min

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

\dfrac{dT}{dt}  = 71.\overline 6 \, ^{\circ } C/min

8 0
2 years ago
In a random sample of 400 residents of Boston, 320 residents indicated that they voted for Obama in the last presidential electi
coldgirl [10]

Answer:

C.I =  0.7608   ≤ p ≤   0.8392

Step-by-step explanation:

Given that:

Let consider a  random sample n = 400 candidates where  320 residents indicated that they voted for Obama

probability \hat p = \dfrac{320}{400}

= 0.8

Level of significance ∝ = 100 -95%

= 5%

= 0.05

The objective is to  develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.

The confidence internal can be computed as:

=\hat p  \pm Z_{\alpha/2} \sqrt{\dfrac{ p(1-p)}{n } }

where;

Z_{0.05/2} = Z_{0.025} = 1.960

SO;

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.8(1-0.8)}{400 } }

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.8(0.2)}{400 } }

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.16}{400 } }

=0.8  \pm 1.960 \sqrt{4 \times 10^{-4}}

=0.8  \pm 1.960 \times 0.02}

=0.8  \pm 0.0392

= 0.8 - 0.0392     OR   0.8 + 0.0392  

= 0.7608    OR    0.8392

Thus; C.I =  0.7608   ≤ p ≤   0.8392

3 0
3 years ago
2(x-+2)+4=6x-4(-1+x)
sertanlavr [38]

2x-4+4=6x+4-4x

2x=2x+4

c there is no solution

8 0
3 years ago
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