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Zanzabum
3 years ago
12

A study done recently 3out of 5 results used brand x how many used brand x out of 2000

Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0
(3/5 )*2000 would give you 1200, which is your answer
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Help!!! I don’t understand how to do this
lidiya [134]

Answer:

  f^{(k)}(x)=\dfrac{17k!(-1)^k}{(x-9)^{k+1}}

Step-by-step explanation:

The question presumes you have access to a computer algebra system. The one I have access to provided the output in the attachment. The list at the bottom is the list of the first four derivatives of f(x).

__

The derivatives alternate signs, so (-1)^k will be a factor.

The numerators start at 17 and increase by increasing factors: 2, 3, 4, indicating k! will be a factor.

The denominators have a degree that is k+1.

Putting these observations together, we can write an expression for the k-th derivative of f(x):

  \boxed{f^{(k)}(x)=\dfrac{17k!(-1)^k}{(x-9)^{k+1}}}

4 0
3 years ago
Set up and solve a proportion 6/100=s/12
rusak2 [61]

Amount of tax on the book (s) is $0.72

Step-by-step explanation:

  • Step 1: Given 6/100 = s/12
  • Step 2: Cross multiply to solve for s

⇒ 6 × 12 = 100 × s

⇒ 72 = 100s

⇒ s = 72/100 = 0.72

7 0
3 years ago
What are the point for a 90 degree rotation counterclockwise about the origin
Korvikt [17]

Answer:

Here is your solution.

6 0
3 years ago
The function f determines the cost (in dollars) of a new Honda Accord in terms of the number of years t since 2000. That is, f (
xenn [34]

Complete  Question

The function f determines the cost (in dollars) of a new Honda Accord in terms of the number of years t since 2000. That is, f ( t ) represents the cost (in dollars) of a new Honda Accord t years after 2000. Use function notation to represent each of the following. The cost (in dollars) of a new Accord in 2006?

A. How much more a new Accord costs in 2013 as compared to the cost of a new Accord in 2010?

B. A new Accord in 2013 is how many times as expensive as a new Accord in 2010?

C. In  2016 , some cars cost  $980 more than the cost of a new Accord.How much does the other cars cost (in dollars)in 2016?

Answer:

a

     The cost of  a new Accord in 2013 compared to 2010 is  z  =  f(13) -  f(10)

b

   The magnitude at which the cost of   a new Accord in 2013 is greater          than the cost in 2010 is  

          x =  \frac{f(13)}{f(10)}

c

    The cost of the other cars is 2016 is   r  =  980 + f(16)

Step-by-step explanation:

From the question we are told that

     The cost (in dollars) of a new Honda Accord is  f(t)

       Where t is  number of years after 2000

The cost of the  Honda Accord at 2013 is  

        f(2013 - 2000) =  f(13)

The cost of the  Honda Accord at 2010 is  

        f(2010 - 2000) =  f(10)

So the cost difference between 2013 and 2010 is mathematically evaluated as

         z  =  f(13) -  f(10)

Let constant at which the cost of Honda Accord in 2013 is greater than its cost at 2010 be  x

So

      f(13) =  x f(10)

=>      x =  \frac{f(13)}{f(10)}

  The cost of the Honda Accord in 2016 is mathematically evaluated as

          f(2016 - 2000) =   f(16)    

Now the cost of these other cars is  mathematically evaluated as  

         r  =  980 + f(16)

7 0
2 years ago
6+6 divided by 6/1-6
pav-90 [236]

Answer:

The answer is 1.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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