Tia has to know the dimensions needed to find the volume of the sculpture. She needs to know the area of the base as well as the height of the pyramid. The formula that she has to use is 1/3*B*h.
4*2=8, 4=number of sections on the spinner, 2=number of sides on a coin
Answer is 1/8 probability
Hope this helps you
Answer:
-1.2 or -11/9 or -1 2/9
Step-by-step explanation:
These are just a few of the things you will learn in 6th grade. You will learn how to write a two- variable equation, how to identify the graph of an equation, graphing two-variable equations. how to interpret a graph and a word problem, and how to write an equation from a graph using a table, two-dimensional figures,Identify and classify polygons, Measure and classify angles,Estimate angle measurements, Classify triangles, Identify trapezoids, Classify quadrilaterals, Graph triangles and quadrilaterals, Find missing angles in triangles, and a lot more subjects. <span><span><span>Find missing angles in quadrilaterals
</span><span>Sums of angles in polygons
</span><span>Lines, line segments, and rays
</span><span>Name angles
</span><span>Complementary and supplementary angles
</span><span>Transversal of parallel lines
</span><span>Find lengths and measures of bisected line segments and angles
</span><span>Parts of a circle
</span><span>Central angles of circles</span></span>Symmetry and transformations
<span><span>Symmetry
</span><span>Reflection, rotation, and translation
</span><span>Translations: graph the image
</span><span>Reflections: graph the image
</span><span>Rotations: graph the image
</span><span>Similar and congruent figures
</span><span>Find side lengths of similar figures</span></span>Three-dimensional figures
<span><span>Identify polyhedra
</span><span>Which figure is being described
</span><span>Nets of three-dimensional figures
</span><span>Front, side, and top view</span></span>Geometric measurement
<span><span>Perimeter
</span><span>Area of rectangles and squares
</span><span>Area of triangles
</span><span>Area of parallelograms and trapezoids
</span><span>Area of quadrilaterals
</span><span>Area of compound figures
</span><span>Area between two rectangles
</span><span>Area between two triangles
</span><span>Rectangles: relationship between perimeter and area
</span><span>compare area and perimeter of two figures
</span><span>Circles: calculate area, circumference, radius, and diameter
</span><span>Circles: word problems
</span><span>Area between two circles
</span><span>Volume of cubes and rectangular prisms
</span><span>Surface area of cubes and rectangular prisms
</span><span>Volume and surface area of triangular prisms
</span><span>Volume and surface area of cylinders
</span><span>Relate volume and surface area
</span><span>Semicircles: calculate area, perimeter, radius, and diameter
</span><span>Quarter circles: calculate area, perimeter, and radius
</span><span>Area of compound figures with triangles, semicircles, and quarter circles</span></span>Data and graphs
<span><span>Interpret pictographs
</span><span>Create pictographs
</span><span>Interpret line plots
</span><span>Create line plots
</span><span>Create and interpret line plots with fractions
</span><span>Create frequency tables
</span><span>Interpret bar graphs
</span><span>Create bar graphs
</span><span>Interpret double bar graphs</span><span>
</span></span><span>
</span></span>
Answer:
the concentration at 10 minutes= 0.4+0.0133= 0.4133%
Step-by-step explanation:
Air containing 0.04% carbon dioxide
V, volume of room is 6000 ft3.
Q, rate of air 2000 ft3/min,
initial concentration of 0.4% carbon dioxide,
determine the subsequent amount in the room at any time.
What is the concentration at 10 minutes?
firstly, we find the time taken for air to completely filled the room
Q = V/t
t = V/Q = 6000/2000 = 3min
so, its take 3mins for air to be completely filled in the room and for exhaust air to move out.
there is an initial concentration of 0.4% carbon dioxide, and the air pump in is 0.04%.
therefore,
3mins = 0.04% of CO2
3*60 =180sec = 0.04%
1sec = 0.04/180 = 0.00022%/sec
so at any time the concentration of CO2 is 0.4 + 0.00022 =0.40022%/sec
What is the concentration at 10 minute
the concentration at 10minutes = the concentration for 1minute because at every minutes, the concentration moves in is moves out. = concentration for 2000ft3.
for 0.04% = 6000ft3
? = 2000ft3
= 2000* 0.04)/6000 =0.0133%
the concentration at 10 minutes= 0.4+0.0133= 0.4133%
