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3 years ago

A 10 month old child has been diagnosed with gastroenteritis. he attends day care what is the most likely cause of the illness

1 answer:

7 0

I think the cause of the illness is Rota-virus. Its a contagious virus that can cause gastroenteritis(inflammation of the stomach and intestines|). Symptoms include severe watery diarrhea, vomiting, fever and abdominal pains. Infants and young children are most likely to get rota virus disease, they become severely dehydrated and can even die.

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In pea plants, long stems are dominant to short stems, purple flowers are dominant to white, and round peas are dominant to wrin

meriva

Assuming the genes are not linked nor interacting with each other, the expected number of long stemmed plants with purple flowers, producing wrinkled peas, L-P-rr, is 288.

<h3>Available data</h3>

long stems are dominant to short stems
purple flowers are dominant to white,
round peas are dominant to wrinkled

Each trait is determined by a single, different gene.

A heter0zyg0us plant is self-crossed
F1) 2,048 descendants

Let us name te alleles as follows

L ⇒ Long stem
l ⇒ Short stem
P ⇒ Purple flowers
p ⇒ white flowers
R ⇒ Round peas
r ⇒ wrinkled peas

Cross) heter0zyg0us plant is self-crossed

Parental) LlPpRr

Gametes) LPR, LPr, LpR, Lpr, lPR, lPr, lpR, lpr

Assuming that these genes are not linked nor interacting with each other, to make the calcs easier we will make crosses considering each gene separately.

Stems

Parental) Ll x Ll

F1) 1/4 LL, 2/4 Ll, 1/4 ll

3/4 long stem, 1/4 short stem

Flower color

Parental) Pp x Pp

F1) 1/4 PP, 2/4 Pp, 1/4 pp

3/4 purple flowers, 1/4 white flowers

Peas

Parental) Rr x Rr

F1) 1/4 RR, 2/4 Rr, 1/4 rr

3/4 round peas, 1/4 wrinkled peas

Now, we will get the proportion of individuals with long stems, purple flowers, producing wrinkled peas, L-P-rr

Note: The symbol - is representing either a dominant or a recessive allele.

From the crosses, we know that

3/4 are long stemmed,
3/4 have purple flowers, and
1/4 have wrinkled peas.

To get the proportion of individuals expressing all these traits together, we just need to multiply these values.

3/4 L- x 3/4 P- x 1/4 rr = 9/64 L-P-rr

Knowing that the total number of plants is 2,048 and that there are 64 possible gametes combinations from this cross, we will use the proportion 9/64 to get the number of plants with these traits.

64 ------------- 2,048 plants

9 -------------- X = (9 x 2048) / 64 = 288 plants.

We expect to find 288 long stemmed plants with purple flowers, producing wrinkled peas.

You will learn more about trihybrid crosses at

brainly.com/question/21942441

brainly.com/question/7333760

brainly.com/question/6764853

4 0

2 years ago

Atoms with a low ionization energy give up their outer valence electrons with ease true or false

umka2103 [35]

Answer: The given statement is true.

Explanation: Ionization energy is defined as the amount of energy required to remove an electron from the outermost shell of an isolated gaseous atom.

General equation of ionization energy is given by:

$X(g)\rightarrow X^+(g)+e^-$

If the outermost electron is loosely bound to the nucleus which means that the electron can be easily removed form an atom, it will require less amount of ionization energy.

And if the outermost electron is tightly bound to the nucleus which means that the electron cannot be removed easily from an atom. And hence, it will require more ionization energy.

Hence, the given statement is true.

6 0

3 years ago

A mite is a tiny organism that may ride on top of an insect, such as a beetle, in order to move quickly from place to place. The

kupik [55]

the answer is the beetle is neither harmed nor helped by the mite.

6 0

3 years ago

Read 2 more answers

Genes A and B are 10 map units apart and genes B and C are 20 map units apart, with gene B located between genes A and C. What w

Marizza181 [45]

Answer:

2% of the progeny will be double crossovers for the trihybrid test cross

Explanation:

By knowing the positions of genes, we can estimate the distances in MU between them per region.

Genes A and B are 10 map units apart (Region I)
Genes B and C are 20 map units apart (Region II)
Genes A and C are 30 map units apart

----A-------10MU--------B-------------20MU-------------C---

Region I Region II

We can estimate the recombination frequencies by dividing each distance by 100.

• recombination frequency of A-B region = 10MU / 100 = 0.10

• recombination frequency of B-C region = 20MU / 100 = 0.20

Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:

EDRF = recombination frequency in region I x recombination frequency in region II.

EDRF = 0.10 x 0.20 = 0.02

2% of the progeny will be double crossovers for the trihybrid test cross

7 0

3 years ago

Fill in the blanks to complete the sentences about why Earth's atmosphere is important to living things. Earth's atmosphere prov

deff fn [24]

Answer:

Earth's atmosphere filters out harmful radiation from the sun.

Explanation:

The sun is earth's star and sunlight helps light up and warm the earth and also helps in the process of photosynthesis. Sunlight on the other hand, produces harmful rays called Ultraviolet radiation or UV rays.

These ultraviolet radiation is dangerous to our skin and ultimately our body as a whole. Fortunately for us, the earth's atmosphere has a protective layer called the Ozone layer. The Ozone layer serves to filter out and block the harmful ultraviolet radiation and prevent it from reaching the earth, thereby protecting us.

Sadly though, the Ozone layer is getting depleted by human activities which emit harmful gases like carbon dioxide into the atmosphere. Activities such as oil drilling, automobile emissions, destruction of forests etc. These activities affect the Ozone layer leading to it's gradual disappearance and letting in the harmful UV rays. A phenomenon referred to as global warming.

8 0

3 years ago

Read 2 more answers