Well a right angle is 90° so all u have to do is take 10° away from that
Answer:
There are 0.475 pounds of apples in each tart.
I arrived in this number by dividing the total number of pounds by the total number of tarts made.
475 pounds divided by 1000 tarts is equal to 0.475 pounds per tart.
475 lbs/1000 tarts = 0.475 lbs/tart
So, if you are to bake a certain number of tarts and need to know the total number of pounds of apple needed to bake you can use this equation.
y = 0.475x
where y represents the total number of pounds needed to bake x number of tarts with a fixed 0.475 pounds per tart.
Step-by-step explanation:
Answer:
The screenshot is not included!!
Answer: 37 units
Step-by-step explanation:
This also works as the height of the triangle.
This also works as the base of the triangle.
Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.
To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.
![s=\sqrt[]{A}](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7BA%7D)
Let's work with Blue.
![s=\sqrt[]{144units^2} \\s=12units](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7B144units%5E2%7D%20%5C%5Cs%3D12units)
Now Pink.
![s=\sqrt[]{1225units^2}\\s=35units](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7B1225units%5E2%7D%5C%5Cs%3D35units)
So we have a triangle with a base of 35 units and a height of 12 units.
Now let's use the pythagoream's theorem to solve.
![c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2%5C%5Cc%3D%5Csqrt%5B%5D%7Ba%5E2%2Bb%5E2%7D%20%5C%5Cc%3D%5Csqrt%5B%5D%7B%2812units%29%5E2%2B%2835units%29%5E2%7D%5C%5Cc%3D%5Csqrt%5B%5D%7B144units%5E2%2B1225units%5E2%7D%5C%5C%20c%3D%5Csqrt%5B%5D%7B1369units%5E2%7D%5C%5C%20c%3D37units)
Assuming you are hoping to obtain the value of "g", to solve worded algebra problems like these, it is easier to translate the world problem into a mathematical equation first.
In this case, "93 is the sum of a number g and 58" can be translated to:
93 = g + 58
To find the value of g, it is necessary to isolate g first. To do this, we subtract both sides of the equation by 58:
93 - 58 = g + 58 - 58
93 - 58 = g
Simplifying:
g = 35
