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ankoles [38]
3 years ago
10

Jan is cutting a rectangular pan of brownies.She cut them in half and then cut each of those halves in half again.She did the sa

me thing going the other direction.How many brownies does she have?

Mathematics
1 answer:
kumpel [21]3 years ago
7 0
I drew a picture!!
.
Maybe you didn't.
.
I like to picture things though.
.
Ok, a rectangle cut in half. 
.
Ok, by definition of "half," just multiply the number of rectangles by 2.
.
1 x 2 = 2 after cutting the brownies in half.
.
2 x 2 = 4 after cutting it in half again.
.
4 rectangles now!!
.
Doing it the other way... pretend you are starting over from scratch.
.
A new batch of brownies!
.
But still pay attention to what you already cut. 
.
Cut down the middle the other direction.
.
What's 4 x 2?
.
8.
.
Now, finally, we multiply the half of the half brownies.
.
What's 8 x 2?
.
16.
.
16 slices.

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In a normal distribution, a data value located 0.8 standard deviations below the mean has Standard Score: z =
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Answer:

answer cuzzz euevaksn

4 0
3 years ago
To test μ for an x distribution that is mound-shaped using sample size n ≥ 30, how do you decide whether to use the normal or st
Luden [163]
Answer:
Use the normal distribution if the population standard deviation is known.
Use the student's t distribution when the population standard deviation is unknown.

Explanation:
A mound-shaped distribution refers to the normal distribution.
A good sample size for testing against the normal distribution should be
n >= 30.
The condition for the sample size is satisfied.
However, we are not given the population standard deviation, therefore it is assumed to be unknown.
Therefore the student's t distribution should be used. 
6 0
3 years ago
The brand manager for a brand toothpaste must plan a campaign designed to increase brand recognition. He wants to first determin
bulgar [2K]

We need to find out how many adults must the brand manager survey in order to be 90% confident that his estimate is within five percentage points of the true population percentage.

From the given data we know that our confidence level is 90%. From Standard Normal Table we know that the critical level at 90% confidence level is 1.645. In other words, Z_{Critical}=1.645.

We also know that E=5% or E=0.05

Also, since, \hat{p} is not given, we will assume that \hat{p}=0.5. This is because, the formula that we use will have \hat{p}(1-\hat{p}) in the expression and that will be maximum only when \hat{p}=0.5. (For any other value of \hat{p}, we will get a value less than 0.25. For example if, \hat{p} is 0.4, then 1-\hat{p}=0.6 and thus, \hat{p}(1-\hat{p})=0.24.).

We will now use the formula

n=(\frac{Z_{Critical}}{E})^2\hat{p}(1-\hat{p})

We will now substitute all the data that we have and we will get

n=(\frac{1.645}{0.05})^2\times0.5(1-0.5)

n=(32.9)^2\times0.25

n=270.6025

which can approximated to n=271.

So, the brand manager needs a sample size of 271

3 0
3 years ago
the cost of 5 cans of dog food is $4.35. at this price how much do 11 cans of dog food cost explain your reasoning. ASAP
mestny [16]

Answer:

Cost of 11 cans of Dog food is $9.57

Step-by-step explanation:

Cost of 5 cans of dog food = $4.35

So to find out the cost of 11 cans of dog food at the same price, we need to calculate the price of 1 can of dog food.

<u>Calculation for finding out cost of 1 can of dog food</u>

The price $4.35 which is given is the price of 5 cans

So to find the cost of 1 can, we need to divide the given price by 5

5 Cans of dog food = $4.35

1 can of dog food = 4.35 ÷ 5

1 can of dog food = $0.87


<em><u>Now to find out the price of 11 cans, we will multiply the price of 1 can with 11</u></em>

Cost of 11 cans = 11 × $0.87

                          = $9.57

6 0
3 years ago
Which one is greater 10.05 or 10.005
Blababa [14]
10.05 = 10 5/100 = 10 1/20
10.005 = 10 5/1000 = 10 1/200

therefore, 10.05 is greater then 10.005
8 0
3 years ago
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