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Allushta [10]
3 years ago
6

Need help solving x

Mathematics
1 answer:
viva [34]3 years ago
5 0

The coefficient of x in the equation is 1/(300 grams). Multiply by the reciprocal of that, which is (300 grams).

x = (300 grams)×(2 grams)/(100 grams) = (300×2/100) grams = 6 grams

_____

This is the way you solve any equation where x is multiplied by some value in the only term on one side of the equal sign.

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earnstyle [38]

Answer:

D

Step-by-step explanation:

100 - 35 = 55 dollars remaining

55/20 = 3.25 hours until no money

4 0
2 years ago
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Can someone help me do part two please? It’s very important send a picture or something. I don’t even care if you tell me the st
Nataly_w [17]
<h3>Explanation:</h3>

1. "Create your own circle on a complex plane."

The equation of a circle in the complex plane can be written a number of ways. For center c (a complex number) and radius r (a positive real number), one formula is ...

  |z-c| = r

If we let c = 2+i and r = 5, the equation becomes ...

  |z -(2+i)| = 5

For z = x + yi and |z| = √(x² +y²), this equation is equivalent to the Cartesian coordinate equation ...

  (x -2)² +(y -1)² = 5²

__

2. "Choose two end points of a diameter to prove the diameter and radius of the circle."

We don't know what "prove the diameter and radius" means. We can show that the chosen end points z₁ and z₂ are 10 units apart, and their midpoint is the center of the circle c.

For the end points of a diameter, we choose ...

  • z₁ = 5 +5i
  • z₂ = -1 -3i

The distance between these is ...

  |z₂ -z₁| = |(-1-5) +(-3-5)i| = |-6 -8i|

  = √((-6)² +(-8)²) = √100

  |z₂ -z₁| = 10 . . . . . . the diameter of a circle of radius 5

The midpoint of these two point should be the center of the circle.

  (z₁ +z₂)/2 = ((5 -1) +(5 -3)i)/2 = (4 +2i)/2 = 2 +i

  (z₁ +z₂)/2 = c . . . . . the center of the circle is the midpoint of the diameter

__₁₂₃₄

3. "Show how to determine the center of the circle."

As with any circle, the center is the <em>midpoint of any diameter</em> (demonstrated in question 2). It is also the point of intersection of the perpendicular bisectors of any chords, and it is equidistant from any points on the circle.

Any of these relations can be used to find the circle center, depending on the information you start with.

As an example. we can choose another point we know to be on the circle:

  z₄ = 6-2i

Using this point and the z₁ and z₂ above, we can write three equations in the "unknown" circle center (a +bi):

  • |z₁ - (a+bi)| = r
  • |z₂ - (a+bi)| = r
  • |z₄ - (a+bi)| = r

Using the formula for the square of the magnitude of a complex number, this becomes ...

  (5-a)² +(5-b)² = r² = 25 -10a +a² +25 -10b +b²

  (-1-a)² +(-3-b)² = r² = 1 +2a +a² +9 +6b +b²

  (6-a)² +(-2-b)² = r² = 36 -12a +a² +4 +4b +b²

Subtracting the first two equations from the third gives two linear equations in a and b:

  11 -2a -21 +14b = 0

  35 -14a -5 -2b = 0

Rearranging these to standard form, we get

  a -7b = -5

  7a +b = 15

Solving these by your favorite method gives ...

  a +bi = 2 +i = c . . . . the center of the circle

__

4. "Choose two points, one on the circle and the other not on the circle. Show, mathematically, how to determine whether or not the point is on the circle."

The points we choose are ...

  • z₃ = 3 -2i
  • z₄ = 6 -2i

We can show whether or not these are on the circle by seeing if they satisfy the equation of the circle.

  |z -c| = 5

For z₃: |(3 -2i) -(2 +i)| = √((3-2)² +(-2-i)²) = √(1+9) = √10 ≠ 5 . . . NOT on circle

For z₄: |(6 -2i) -(2 +i)| = √((6 -2)² +(2 -i)²) = √(16 +9) = √25 = 5 . . . IS on circle

4 0
3 years ago
Researchers are interested in the effect of a certain nutrient on the growth rate of plant seedlings. Using a hydroponics growth
emmainna [20.7K]

Answer:

\bar{x}=61.98

Step-by-step explanation:

The sample mean \bar{x} is a point estimate of the population mean μ.

Given the heights of the 6 tomato plants sample below:

55.6, 59.4, 59.9, 62.9, 64.9, 69.2

Point Estimate,

\bar{x}=\dfrac{55.6+59.4+59.9+62.9+64.9+69.2}{6} \\=\dfrac{371.9}{6} \\\bar{x}=61.98

4 0
3 years ago
By rounding to 1 significant figure, estimate the answers to these questions:<br><br> 346 x 904
nikdorinn [45]

Answer:

    312 784

Step-by-step explanation:

   if u need this answer, take

8 0
3 years ago
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The line segment joining the points A(2,1) and B(5,-8) is trisected at the points p and q such that p is nearer to A. If p also
SpyIntel [72]

Answer:

  k = -8

Step-by-step explanation:

The location of P is ...

  P = (2A+B)/3 = (2·2+5, 2·1-8)/3 = (3, -2)

Putting this point into the equation for the line, we have ...

  2(3) -(-2) +k = 0

  8 +k = 0

  k = -8

3 0
3 years ago
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