Answer:
97,99,101,103
Step-by-step explanation:
Let x = first odd integer
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+6 = 4th odd integer
Sum of 4 odd integers is 400
x+ (x+2) + (x+4)+(x+6) = 400
Combine like terms
4x +12 = 400
Subtract 12 from each side
4x+12-12 = 400-12
4x = 388
Divide by 4 on each side
4x/4 = 388/4
x=97
The first integer is 97
The 2nd is 97+2 =99
The third ix 97+4 = 101
The 4th is 97+6 = 103
Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
If she works 40 hours getting paid $12 an hour she will get $480
Short answer: the same way you do it with any other kind of numbers.
"Place value" means the value of a number comes from where it is (its place) in relation to the decimal point. The digit immediately to the left of the decimal point is the units digit, so tells you the number of units represented.
Each digit to the left of the units digit has a place value that is 10 times that of the digit to its right. Each digit to the right of the units digit (hence to the right of the decimal point) has a place value that is 1/10 that of the digit to its left.
The places have names (see attached).
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You can find the place value of a digit by setting all the other digits in the number to zero. For example, the place value of 2 in the number 324 is 020, or 20.
you just do 144 divided by 8. There are 18 members of the class.
