1: 72
2: 32
3: 1/2
I think this is it
A reasonable function is W = 7F + 5000
Where W is the weight of the plane and F is the number of gallons of fuel.
The domain is the set of possible values for F. That is from 0 (empty tank) to 400 (full tank).
So the domain is F = [0,400], or what is equivalente 0 ≤ F ≤ 400.
The range is the set of values of W.
The minimum value of W is when F = 0 => W = 7(0) + 5000 = 5,000.
The maximum value of W is when F = 400 => W = 7(400) + 5000 = 7,800
So the range is W = [5,000 ; 7,800], pr 5000 ≤ W ≤ 7,800.
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-9)^2+y^2=4\implies (x-\stackrel{h}{9})^2+(y-\stackrel{k}{0})^2=2^2~\hfill \stackrel{center}{(9,0)} \\\\\\ (x-\stackrel{h}{3})^2+(y-\stackrel{k}{2})^2=4\implies (x-\stackrel{h}{3})^2+(y-\stackrel{k}{2})^2=2^2~\hfill \stackrel{center}{(3,2)}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%20%5Cqquad%20center~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20radius%3D%5Cstackrel%7B%7D%7B%20r%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%28x-9%29%5E2%2By%5E2%3D4%5Cimplies%20%28x-%5Cstackrel%7Bh%7D%7B9%7D%29%5E2%2B%28y-%5Cstackrel%7Bk%7D%7B0%7D%29%5E2%3D2%5E2~%5Chfill%20%5Cstackrel%7Bcenter%7D%7B%289%2C0%29%7D%20%5C%5C%5C%5C%5C%5C%20%28x-%5Cstackrel%7Bh%7D%7B3%7D%29%5E2%2B%28y-%5Cstackrel%7Bk%7D%7B2%7D%29%5E2%3D4%5Cimplies%20%28x-%5Cstackrel%7Bh%7D%7B3%7D%29%5E2%2B%28y-%5Cstackrel%7Bk%7D%7B2%7D%29%5E2%3D2%5E2~%5Chfill%20%5Cstackrel%7Bcenter%7D%7B%283%2C2%29%7D)
Check the picture below.
well, its radius didn't change, anyhow, you know what to check out.
Stretched by 3, right 2, up 1
