The theoretical yield of H₂S is 13.5 g.
The percent yield is 75.5 %.
<h3>What is the theoretical yield of H₂S from the reaction?</h3>
The equation of the reaction is given below:
Moles of FeS reacting = mass/molar mass
Molar mass of FeS = 88 g/mol
Moles of FeS reacting = 35/88 = 0.398 moles
Moles of H₂S produced = 0.398 moles
Molar mass of H₂S = 34 g/mol
Mass of H₂S produced = 0.398 * 34 = 13.5 g
Theoretical yield of H₂S is 13.5 g.
- Percent yield = actual yield/theoretical yield * 100%
Actual yield of H₂S = 10.2 g
Percent yield = 10.2/13.5 * 100%
Percent yield = 75.5 %
In conclusion, the actual yield is less than the theoretical yield.
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Answer: 0.45 J / g °C
Explanation: solution attached.
Heat is equal to the product of mass, specific heat and change in temperature.
Q= mc∆T
Derive the equation to find c
c = Q / m∆T substitute the values
c = 21.6 J / 2.0g ( 24°C - 5°C)
c = 0.45 J / g ° C
Answer: false
Explanation: Reason being A substance cannot be a gas or a mixture, only can a pure substance that occurs in nature may
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Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure
Use the ideal gas law, given by

where
V = volume
R = 8.3145 J/(mol-K), the gas constant
Therefore,

Answer: 0.363 m³