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k0ka [10]
3 years ago
15

How do scientists design a system?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
3 0

Answer: D

Explanation:

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How many mg of O2 will react with the TNT?
Tanzania [10]
 TNT has the molecular formula: C7H5N3O6. And hence, when reacted in oxygen gas, you get what is known as <span>combustion</span> reaction. the reaction is: <span><span>C7</span><span>H5</span><span>N3</span><span>O6</span>+<span>O2</span>→C<span>O2</span>+<span>N2</span>+<span>H2</span><span>O</span></span>
6 0
3 years ago
Compounds like CCl₂F₂ are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are n
natta225 [31]

Answer: Mass Of CFC that needs to evaporate for the freezing of water = 328.24 g

Explanation: Heat gained by the CFC = Heat lost by water

Heat lost by water = Heat required to take water's temperature to 0°c + Heat required to freeze water at 0°c

Heat required to take water's temperature from 33°c to 0°c = mCΔT

m = 201g, C = 4.18 J/(gK), ΔT = 33

mCΔT = 201 × 4.18 × 33 = 27725.94 J

Heat required to freeze water at 0°c = mL

m = 201g, L = 334 J/g

mL = 201 × 334 = 67134 J

Heat gained by CFC to vaporize = mH = 27725.94 + 67134 = 94859.94 J

H = 289 J/g, m = ?

m × 289 = 94859.9

m = 328.24 g

QED!!

7 0
3 years ago
Which of the following characteristics would make a gas non-ideal?
Marysya12 [62]

Answer:

A. The gas molecules possess kinetic energy.

Explanation:

The characteristics of the Ideal gases are given by the Kinetic Theory of gases which are as follows:-

Gases consist of particles in constant, random motion. They continue in a straight line until they collide with something—usually each other or the walls of their container.

Particles are point masses with no volume. The particles are so small compared to the space between them, that we do not consider their size in ideal gases.

No molecular forces are at work. This means that there is no attraction or repulsion between the particles.

Gas pressure is due to the molecules colliding with the walls

8 0
3 years ago
a sample of an unknown metal has a mass of 21.6g and volume of an 8.00cm3 calculate the density of the unknown metal
Strike441 [17]

Answer:

<h2>2.70 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{21.6}{8}  \\  = 2.7

We have the final answer as

<h3>2.70 g/cm³</h3>

Hope this helps you

4 0
3 years ago
What is the density of air at 75 F and latm pressure? Express in lbm/ft3 and kg/m3
ser-zykov [4K]

Answer : The density of air in lbm/ft^3 and kg/m^3 is, 0.0743lbm/ft^3 and 1.19kg/m^3 respectively.

Explanation :

PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}

where,

P = pressure of air = 1 atm

V = volume of air

T = temperature of air = 297 K

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

^oC=(75-32)\times \frac{5}{9}=24^oC

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273+^oC

K=273+24=297K

n = number of moles

m = mass of air

M = average molar mass of air = 28.97 g/mole

\rho = density of air = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the above formula, we get:

\rho=\frac{PM}{RT}

\rho=\frac{(1atm)\times (28.97g/mole)}{(0.0821L.atm/mol.K)\times (297K)}

\rho=1.19g/L

Now we have to calculate density in lbm/ft^3.

Conversion used :

1g/L=0.0624lbm/ft^3

So,

1.19g/L=\frac{1.19g/L}{1g/L}\times 0.0624lbm/ft^3=0.0743lbm/ft^3

The density of air in lbm/ft^3 is, 0.0743lbm/ft^3

Now we have to calculate density in kg/m^3.

Conversion used :

1g/L=1kg/m^3

So,

1.19g/L=1.19kg/m^3

The density of air in kg/m^3 is, 1.19kg/m^3

8 0
3 years ago
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