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Westkost [7]
3 years ago
8

Explain why, even though a collision may have energy in excess of the activation energy, what reaction may not occur ?

Chemistry
1 answer:
Nata [24]3 years ago
4 0

Activation energy is the energy needed to start a reaction, eg the flame needed to start ... Collisions may have enough energy to react yet not react if the orientation of the molecules is incorrect. Difficult to explain here without graphics, but basically of the molecules are facing the wrong way it won't happen.

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Metals posses varying reduction potentials. Iron can reduce Cu+2 (aq) to copper metal. Silver can reduce Au+ (aq) to gold metal.
natta225 [31]

<u>Answer:</u> The true statement is iron can reduce Au^+(aq) to gold metal

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

A+BC\rightarrow AC+B

Metal A is more reactive than metal B.

We are given:

Iron can reduce copper, silver can reduce gold, sodium can reduce iron and copper can reduce silver metal.

The increasing order of reactivity thus follows:

Au

where, sodium is most reactive and gold is least reactive

For the given options:

<u>Option 1:</u>  Copper cannot easily reduce sodium ion to sodium metal because it is less reactive.

Cu(s)+Na^+(aq.)\rightarrow \text{ No reaction}

<u>Option 2:</u>  Iron cant easily reduce gold ion to gold metal because it is more reactive.

Fe(s)+3Au^+(aq.)\rightarrow Fe^{3+}(aq.)+3Au(s)

<u>Option 3:</u>  Silver cannot easily reduce iron ion to iron metal because it is less reactive.

Ag(s)+Fe^{3+}(aq.)\rightarrow \text{ No reaction}

Hence, the true statement is iron can reduce Au^+(aq) to gold metal

7 0
3 years ago
Ap sublevel has 3 electrons. How should they be arranged
galina1969 [7]

Answer:

C.)One electron in each p orbital

Explanation:

In a P-sublevel with 3 electrons, they should be arranged with one electron going into each p-orbitals.

This is in accordance with the Hund's rule of maximum multiplicity.

The rule states that "electrons go into degenerate orbitals or sub-levels(p,d and f) singly before paring up".

Since the p-orbital is 3-fold degenerate with a capacity to accommodate a maximum number of 6 electrons, given 3 electrons, they will follow the Hund's rule in order to fill the orbitals.

So one electron will go in each p - orbitals easily.  

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