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3 years ago

60 POINTS BRAINLIEST

Mathematics

2 answers:

Mariana [72]3 years ago

5 0

60 POINTS BRAINLIEST

ANSWER QUESTIONS A B & C

PHOTO ATTACHED BELOW !!!!

A) Using the given spreadsheet as a basis, discuss the usefulness of a standard

deviation in a given dataset. You need to cite any literature sources you use.

B) Produce an appropriate fully-labeled chart to compare the gold, silver and

bronze medals totals of the 10 countries.

C) Use a suitable and fully-labeled chart to reflect the contribution of each

country to the overall medals total.

PLEASE HELP DUE TODAY!!60 POINTS BRAINLIEST

ANSWER QUESTIONS A B & C

PHOTO ATTACHED BELOW !!!!

A) Using the given spreadsheet as a basis, discuss the usefulness of a standard

deviation in a given dataset. You need to cite any literature sources you use.

B) Produce an appropriate fully-labeled chart to compare the gold, silver and

bronze medals totals of the 10 countries.

C) Use a suitable and fully-labeled chart to reflect the contribution of each

country to the overall medals total.

PLEASE HELP DUE TODAY!!60 POINTS BRAINLIEST

ANSWER QUESTIONS A B & C

PHOTO ATTACHED BELOW !!!!

A) Using the given spreadsheet as a basis, discuss the usefulness of a standard

deviation in a given dataset. You need to cite any literature sources you use.

B) Produce an appropriate fully-labeled chart to compare the gold, silver and

bronze medals totals of the 10 countries.

C) Use a suitable and fully-labeled chart to reflect the contribution of each

country to the overall medals total.

PLEASE HELP DUE TODAY!!

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Ira Lisetskai [31]3 years ago

5 0

Answer:

wait what are we supposed to do

Step-by-step explanation:

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I need help fast please I don’t understand this and I’ve been struggling for a while. Can I get a brain list please or a tutor t

solong [7]

Answer:

4 √6

Step-by-step explanation:

We have a few right triangles. We know that a²+b²=c², with c being the side opposite the right angle. Representing the side without a value as z, we have:

m²+z² = (8+4)² = 12²

4²+n²=z²

8²+n²=m²

We have 3 equations with 3 unknown variables, so this should be solvable. One way to find a solution is to put everything in terms of m and go from there. First, we can take n out of the equations entirely, removing one variable. We can do this by solving for it in terms of z and plugging that into the third equation, removing a variable as well as an equation.

4²+n²=z²

subtract 4²=16 from both sides

z²-16 = n²

plug that into the third equation

64 + z² - 16 = m²

48 + z² = m²

subtract 48 from both sides to solve for z²

z² = m² - 48

plug that into the first equation

m² + m² - 48 = 144

2m² - 48 = 144

add 48 to both sides to isolate the m² and its coefficient

192 = 2m²

divide both sides by 2 to isolate the m²

96 = m²

square root both sides to solve for m

√96 = m

we know that 96 = 16 * 6, and 16 = 4², so

m = √96 = √(4²*6) = 4 √6

5 0

2 years ago

Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa

Nataly_w [17]

Answer:

The first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

coefficient of $x^{2}$ in the expansion of $(2+x - x^{2})^{6}$ = (240 - 192) = 48

Step-by-step explanation:

$(2+x)^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})$

= $6_{C_{0}} \times x^{0} \times 2^{6} + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4}$ + terms involving higher powers of x