According to Einstein, increasing the brightness (or intensity) of a beam of light without changing its color will increase (cir
1 answer:
You might be interested in
Answer: In both ionic and molecular bonds, the resulting compound is stabilized because each atom's outer electronic orbital is full.
Explanation:
Molecular bonds are also called covalent bonds. A covalent bond is formed by sharing of electrons between two or more atoms.
For example, atomic number of hydrogen is 1 and atomic number of nitrogen is 7 (2, 5). In order to attain stability hydrogen atom needs to gain one electron whereas nitrogen needs to gain 3 electrons.
Hence, 3 atoms of hydrogen chemically combine with one atom of nitrogen by sharing electrons and thus it forms the compound .
Ionic bonds are the bonds formed by transfer of electrons from one atom to another.
For example, atomic number of sodium is 11 (2, 8, 1) and atomic number of chlorine is 17 (2, 8, 7). In order to attain stability sodium needs to lose one electron whereas chlorine needs to gain one electron.
Hence, when sodium combines chemically with chloride then sodium will transfer its 1 valence electron to the chlorine atom and thus it forms the compound NaCl.
Therefore, we can conclude that in both ionic and molecular bonds, the resulting compound is stabilized because each atom's outer electronic orbital is full.
Answer:
Explanation:
M = Mass of Uranus
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Uranus = 25360 km
h = Altitude = 104000 km
= Radius of Miranda = 236 km
m = Mass of Miranda =
Acceleration due to gravity is given by
The mass of Uranus is
Acceleration is given by
Miranda's acceleration due to its orbital motion about Uranus is
On Miranda
Acceleration due to Miranda's gravity at the surface of Miranda is
No, both the objects will fall towards Uranus. Also, they are not stationary.
Apply the Pythagorean theorem to get the resultant velocity:
V =
Given values:
Vx = 57.8m/s
Vy = 5.6m/s
Plug in and solve for V:
V = 58.1m/s
EDIT: Let's get the direction of the resultant velocity as well.
This equation will give the angle of the velocity as measured off of the ground:
θ = tan⁻¹(Vy/Vx)
Again, the given values are:
Vx = 57.8m/s
Vy = 5.6m/s
Plug in the values and solve for the angle θ:
θ = tan⁻¹(5.6/57.8)
θ = 5.5°
The resultant velocity is oriented 5.5° off the ground.