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3 years ago

A 4.0-kg meatball is moving to the right with a speed of 6.0 m/s directly toward a 2.0 kg meatball

Physics

1 answer:

Artist 52 [7]3 years ago

3 0

Answer:

Explanation:

The equation for this is the one for the Law of Momentum Conservation which says that the momentum before the collision of the balls has to be the same after the collision because momentum cannot be created or destroyed. For us in particular:

$[(m_1v_1+m_2v_2)]_b=[(m_1+m_2)v_{both}]_a$ and filling in:

[(4.0)(6.0) + (2.0)(0)] = [(4.0 + 2.0)v] and

24 + 0 = 6.0v and

24 = 6.0v so

v = 4.0 m/s to the right

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Light of wavelength 550 nm falls on a

Brums [2.3K]

Answer:

The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.

Explanation:

We can describe single slit diffraction phenomenon with the equation:

$a\sin\theta=m\lambda$ (1)

with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum ( $y_{m}$ ) are small compared to the distance between the screen and the slit (x), we can approximate $\sin\theta\approx\tan\theta=\frac{y}{x}$ , using this on (1):

$a\frac{y_{m}}{x}=m\lambda$

solving for y

$y_{m}= \frac{mx\lambda}{a}$

Note that $y_{m}$ is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find $y_{1}$ , $y_{2}$ add them and divide by two:

$y_{1}= \frac{(1)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}$

$y_{1}= 1.8 m$

$y_{2}= \frac{(2)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}$

$y_{1}= 3.6 m$

$maximum = \frac{1.8+3.6}{2}=2.7m$

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3 years ago

How many seconds would it take a radio wave to travel from the planet Venus to

xz_007 [3.2K]

Answer:

La distancia media de Venus al Sol es de 108.159.260,51 Km

La distancia media de la Tierra al Sol: 149.597.870,691 Km

La diferencia entre una y otra distancia media te darÃ¡ el promedio de distancia de la Tierra a Venus: 41.438.618,181 Km.

Siendo la velocidad de la luz: 299.792,458 Km / seg

Divides: 41.438.618,181 Km / 299.792,458 Km / seg = 138,22433 segundos

138,22433 seg / 60 seg = 2,30374 minutos

Este tiempo es el que tarda la onda de radio en viajar del planeta Venus a la Tierra.

La velocidad de la onda de radio se conviene en considerarla igual al de la velocidad de la Luz en el vacÃo.

Explanation:

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3 years ago

Animals exhale _____. oxygen glucose carbon carbon dioxide

blondinia [14]

Answer:

carbon dioxide

Explanation:

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3 years ago

Read 2 more answers

How much work w is done by the electrostatic force on the moving point charge?

V125BC [204]

As we know that electrostatic force is a conservative force

so we can say by the condition of conservative force

$F_c = -\frac{dU}{dr}$

here we can rearrange the above equation as

$dU = - F_c.dr$

now integrate both sides

$\int dU = - \int F_c . dr$

Now we know by the definition of work done by a force is given by

$W = \int F.dr$

now work done by conservative force is given as

$W_c = \int F_c . dr$

Now from above work done by electric field to move charge from one point to other is given as

$W_{EF} = \int F_{e}.dr = - \int dU$

so here work done is given as

$W_{EF} = U_i - U_f$

so change in potential energy is given by work done

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4 years ago

It takes much longer to bake a whole potato than potatoes that have been cut into pieces why ?

anzhelika [568]

A whole potato must be cooked from outside in, just like a potato cut into slices.

however, with a potato cut into slices, there is a greater surface area, so there is more "outside" and less inside. as a result, the sliced potato cooks faster.

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3 years ago