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Serhud [2]
3 years ago
10

In both ionic and molecular bonds, the resulting compound is stabilized because

Physics
1 answer:
frosja888 [35]3 years ago
7 0

Answer: In both ionic and molecular bonds, the resulting compound is stabilized because each atom's outer electronic orbital is full.

Explanation:

Molecular bonds are also called covalent bonds. A covalent bond is formed by sharing of electrons between two or more atoms.

For example, atomic number of hydrogen is 1 and atomic number of nitrogen is 7 (2, 5). In order to attain stability hydrogen atom needs to gain one electron whereas nitrogen needs to gain 3 electrons.

Hence, 3 atoms of hydrogen chemically combine with one atom of nitrogen by sharing electrons and thus it forms the compound NH_{3}.

Ionic bonds are the bonds formed by transfer of electrons from one atom to another.

For example, atomic number of sodium is 11 (2, 8, 1) and atomic number of chlorine is 17 (2, 8, 7). In order to attain stability sodium needs to lose one electron whereas chlorine needs to gain one electron.

Hence, when sodium combines chemically with chloride then sodium will transfer its 1 valence electron to the chlorine atom and thus it forms the compound NaCl.

Therefore, we can conclude that in both ionic and molecular bonds, the resulting compound is stabilized because each atom's outer electronic orbital is full.

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The maximum force that a grocery bag can withstand without ripping is 250 n. Suppose that the bag is filled with 20 kg of grocer
zhannawk [14.2K]

Answer:

Groceries stay in the bag.

Explanation:

Given:

Maximum force = 250 N

Bag filled with = 20 kg

Lifted acceleration = 5.0\ m/s^2

Solution:

We need to calculate the exerted force on the grocery bag by using Newton's second law.

F = ma

Where:

F = Exerted force on the object.

m = Mass of the object in kg

a = Acceleration of the object in m/s^2

Now, we substitute m = 20 kg and a = 5.0\ m/s^2 in Newton's second law,

F = 20\times 5.0

F = 100\ m/s^2

Since, the exerted force on the bag is less than 250 N, the groceries will stay in the bag.

3 0
3 years ago
What is the KE if a 10kg mass traveling at 5 m/s
11111nata11111 [884]

Answer: KE = 25 J

Explanation: You must use the formula

KE = 1/2 m v²

to solve this problem.

KE = 1/2 (10 Kg) (5 m/s)

KE = 1/2 (50 kgm/s)

KE = 25 J

7 0
3 years ago
Farmer Tamar airlifted her sheep from 1000 meters to 1,200 meters
attashe74 [19]

Question

What was the change in potential energy of the sheep?

Answer:

1962(m) J

Explanation:

Potential energy is given by

PE=mgh

Change in potential energy is given by

∆PE=mg(h2-h1)

Where ∆PE is the change in potential eneegy, g is acceleration due to gravity, h2 is final height and h1 is the initial height.

Substituting 9.81 m/s² for g, 1200 m for h2 and 1000 m for h1 then

∆PE=m*9.81(1200-1000)=1962m Joules

Since we are not given the mass of rhe sheep, the answer will be 1962(m) Joules

4 0
3 years ago
The free length of the spring that is attached to the 0.3-lb slider is 3 in. If the slider is released from rest when x = 6 in.,
hichkok12 [17]

Answer:

a = 64 ft / s²

Explanation:

The force in a spring is given by Hooke's law

          F = -k x

Let's use the initial data to calculate the spring constant

         k = F / x

Reduscate to the English system

          x = 3 in (1foot/12 in) =0.25 foot

         k = 0.3 / 0.25

         k = 1.2  lb / foot

Now we can use Newton's second law

        F = ma

        a = F / m

        a = -k x / m

        m = w / g

        m = 0.3 / 32 = 0.009375

         x= 6 in (1foot /12 in)= 0.5 foot

        a = - 1.2  0.5  / 0.009375

        a = 64 ft / s²

5 0
3 years ago
I need help with this whole work sheet:/
Leokris [45]
Ill give you the formula 

V=I*R

R=V/I

I=V/R
3 0
3 years ago
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