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4 years ago

State two importance of soil air to plants

Chemistry

2 answers:

olya-2409 [2.1K]4 years ago

4 0

soil air helps to release plants nutrients to d soil
it helps different biological processes to take place in the soil
.....................hope this helps

Naddik [55]4 years ago

3 0

Answer:

Soil contains minerals such as Iron, Zinc, Nitrogen compounds, etc. that are all essential to sustaining life. It also holds water and makes it available for plants to use. Soil also contains ores from which we can extract metals such as iron, copper, gold, and aluminum.

(Hope this helps) Sky

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Why is it important for people to understand how to properly dispose of waste in a watershed?

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Answer:

disposing waste properly is important because watersheds are the surface water features and stormwater runoff within a watershed which ultimately end up in other bodies of water. It is essential to consider these downstream impacts when developing and implementing water quality protection and restoration actions. Everything upstream ends up downstream

Explanation:

A watershed describes an area of land that contains a common set of streams and rivers that all drain into a single larger body of water, such as a larger river, a lake or an ocean. For example, the Nile River watershed is an enormous watershed

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4 years ago

Consider the following reaction: COCl2(g) ⇌ CO(g) + Cl2(g) A reaction mixture initially contains 1.6 M COCl2. Determine the equi

professor190 [17]

Answer:

The equilibrium concentration of CO is 0.0361 M

Explanation:

Step 1: Data given

Kc = 8.33 *10^-4

Molarity of COCl2 = 1.6 M

Step 2: The balanced equation:

COCl2(g) ⇌ CO(g) + Cl2(g)

Step 3: Calculate final concentrations

The initial concentration of COCl2 = 1.6M

The initial concentration of CO and Cl2 = 0M

There will react xM of COCl2

Since the mole ratio is 1:1

The final concentration of CO and Cl2 will be X M

The final concentration of COCl2 will be (1.6 -X)M

Step 4: Define Kc

Kc= [CO] *[Cl2] / [COCl2] = 8.33*10^-4

Kc = X*X / 1.6-X = 8.33 * 10^-4

8.33 * 10^-4 = X² /(1.6-X)

8.33 * 10^-4 *(1.6 -X) = X²

0.0013328 - 8.33*10^-4 X = X²

X² + 8.33*10^-4 X - 0.0013328= 0

X = 0.0361 M = [CO] = [Cl2]

[COCl2] = 1.6 - 0.0361 = 1.5639 M

To control this we can calculate the Kc

(0.0361*0.0361)/1.5639 = 0.000833

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3 years ago

Which statement below describes an atomic emission spectra?

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ANSWER- B

Atomic emission spectra are produced when excited electrons return to the ground state. The emitted light corresponds to energies of the specific electrons.

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3 years ago

Read 2 more answers

1). If the molarity of a KCl (potassium chloride) solution is 8.0 M, which of these is true?

Olin [163]

Q. No. 1 is Incomplete.

___________________________________________

Q. No.2: A saline solution contains 0.015 mol NaCl in exactly 0.10 L of solution. What is the molarity of the solution?

Answer:

Molarity = 0.15 mol.L⁻¹ (or) 0.15 M

Solution:

Molarity is the the unit of concentration and it is expressed as the amount of solute dissolved per unit volume of solution. It is expressed as,

Molarity = Moles / Volume of Solution (1)

Data Given;

Moles = 0.015 mol

Volume = 0.10 L

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.015 mol ÷ 0.10 L

Molarity = 0.15 mol.L⁻¹ (or) 0.15 M

___________________________________________

Q. No.3: A solution is prepared by dissolving 42.23 g of NH₄Cl into enough water to make 0.500 L of solution. Calculate its molarity.

Answer:

Molarity = 1.578 mol.L⁻¹ (or) 1.578 M

Solution:

Data Given;

Mass = 42.23 g

Volume = 0.50 L

M.Mass of NH₄Cl = 53.49 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 42.23 g / 53.49 g.mol⁻¹

Moles = 0.789 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.789 mol ÷ 0.50 L

Molarity = 1.578 mol.L⁻¹ (or) 1.578 M

___________________________________________

Q. No.4: Determine the concentration of a solution made by dissolving 10.0 g of sodium chloride (NaCl) in 0.75 L of solution.

Answer:

Molarity = 0.228 mol.L⁻¹ (or) 0.228 M

Solution:

Data Given;

Mass = 10.0 g

Volume = 0.75 L

M.Mass of NaCl = 58.44 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 10.0 g / 58.44 g.mol⁻¹

Moles = 0.171 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.171 mol ÷ 0.75 L

Molarity = 0.228 mol.L⁻¹ (or) 0.228 M

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Q. No.5: Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl₂) in 0.30 L of solution.

Answer:

Molarity = 1.32 mol.L⁻¹ (or) 1.32 M

Solution:

Data Given;

Mass = 44.0 g

Volume = 0.30 L

M.Mass of CaCl₂ = 110.98 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 44.0 g / 110.98 g.mol⁻¹

Moles = 0.396 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.396 mol ÷ 0.30 L

Molarity = 1.32 mol.L⁻¹ (or) 1.32 M

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4 years ago

What are the units of k in the following expression: rate = k [A][B]?s-1M-1s-1M-2s-1M

SVETLANKA909090 [29]

Rate of the reaction is represented as

Rate=k[A][B]

Rate represents change in product concentration with time that has a unit Ms- Whereas concentration of each reactant can be represented as M . so the expression will become:

Ms-1=k[M][M]

k=M-1 s-1.

7 0

3 years ago

Read 2 more answers

State two importance of soil air to plants​

State two importance of soil air to plants