Answer: 2
Explanation:
1) Table (given):
<span>Initial Concentration mol/L Initial Concentration mol/ Initial Rate mol/Ls
[A] [B]
0.20 0.10 20
0.20 0.20 40
0.40 0.20 160
2) Procedure
i) Start assuming the form of the law: r = k [A]ᵃ [B]ᵇ
ii) Comparing row 2 with row 3, you infere that doubling the initial concentration of A and keeping the concentration of B constant, the speed of the reaction quadruples.
That means that the exponent a, or the order of reaction for the reactant A is 2.
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1st half-life: 100%/2 = 50%
2nd half-life: 50%/2 = 25% + 50% (from first half-life)
3rd half-life: 25%/2 = 12.5% + 75% (from first and second half-lives
I looked it up...
2.204 1.16thoae are the answer
We are given with the reaction HCOOH(g) →CO2(g) + H2 (g). According to Dalton's law, the total pressure of a vessel is equal to the sum of the partial pressure of the components inside it. In this case, we plot first the data ln (ratio partial pressure of HCOOH to total pressure) vs time. Partial pressure is the difference of pressure (from one point to another). In this case, the equation is ln P(HCCOH) = -0.0146t - 0.2281 where R² = 0.9923. K is equal to <span> -0.0146 s-1. When the total pressure is 291, ln P is -0.66938, thus the time is 30.23 seconds. The half life is ln(0.5)/k equal to 47.46 seconds.</span>
Answer:
When additional product is added, the equilibrium shifts to reactants to reduce the stress. If reactant or product is removed, the equilibrium shifts to make more reactant or product, respectively, to make up for the loss.