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SVEN [57.7K]
3 years ago
7

The problem is in the pictures, please show step by step how to do it. Thanks! :)

Mathematics
2 answers:
Rama09 [41]3 years ago
7 0

Answer:

-4,-5/2

Step-by-step explanation:

2x^2+3x-20 =0

2x^2+8x-5x-20 =0

2x(x+4)-5(x+4) =0

(x+4)(2x-5) =0

Either,

x+4=0

x=-4

Or,

2x-5=0

2x=5

x=5/2

vlada-n [284]3 years ago
5 0

2x^2+3x-20=0\\2x^2+8x-5x-20=0\\2x(x+4)-5(x+4)=0\\(2x-5)(x+4)=0\\x=\dfrac{5}{2} \vee x=-4

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