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SVEN [57.7K]
3 years ago
7

The problem is in the pictures, please show step by step how to do it. Thanks! :)

Mathematics
2 answers:
Rama09 [41]3 years ago
7 0

Answer:

-4,-5/2

Step-by-step explanation:

2x^2+3x-20 =0

2x^2+8x-5x-20 =0

2x(x+4)-5(x+4) =0

(x+4)(2x-5) =0

Either,

x+4=0

x=-4

Or,

2x-5=0

2x=5

x=5/2

vlada-n [284]3 years ago
5 0

2x^2+3x-20=0\\2x^2+8x-5x-20=0\\2x(x+4)-5(x+4)=0\\(2x-5)(x+4)=0\\x=\dfrac{5}{2} \vee x=-4

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What are two ratios equivalent to 10:85
guajiro [1.7K]

Answer:

2 : 17

1 : 8.5

6 0
3 years ago
1
Svet_ta [14]

Answer:

108π

Step-by-step explanation:

1/3 × 9 × π × (6²)

1/3 × 9π6²

(1 × 9π6²) / 3

(6² × 9π) / 3

6² × 3π

36 × 3π

108π

7 0
3 years ago
How do you solve #23?
scZoUnD [109]

Answer:

m= 67.5 and n=56.25

Step-by-step explanation:

  180-15=165

  165/2= 82.5

  90-15= 75

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7 0
1 year ago
Read 2 more answers
Two lines, A and B, are represented by the following equations: Line A: y = x − 1 Line B: y = −3x + 11 Which of the following op
Nikitich [7]
The answer for the first one is (3,2) because both lines pass through this point. :)
8 0
3 years ago
Find the area of the shaded region. (You may express your answer in<br><br>terms of π.)
erastova [34]

Answer:

a. 16π cm²

b. 24π cm²

c. 33 1/3π cm²

d. 64π-128 cm²

e. 144π-288 cm²

Step-by-step explanation:

To find area of shaded region, find area of whole circle then divide the area where you're left with the area of the shaded region. For the problems with the triangles you find the area of the triangle then subtract that from a fourth of the area of the circle.

Area of a circle = πr²

a.

r=8cm

Area of circle=64π cm²

Shaded region=16π cm²

b.

r=12cm

Area of circle=144π cm²

Shaded region=24π cm²

c.

r=10cm

Area of circle=100π cm²

Shaded region=33 1/3π cm²

d.

r=16cm

Area of circle=256π cm²

Area of triangle=128 cm²

Shaded region=64π-128 cm²

e.

r=24

Area of circle=576π cm²

Area of triangle=288 cm²

Shaded region=144π-288 cm²

4 0
3 years ago
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