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topjm [15]
3 years ago
7

Calculate the force exerted on the blown dart. A dart weighing 0.0056kg is blown and travels 4.85m. The change in velocity for t

he dart is 11.4m/s.
Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

0.15N

Step-by-step explanation:

Given data

Mass= 0.0056kg

distance=  4.85m

Velocity= 11.4m/s

The expression for the force is

F= mv^2/r

substitute

F=  0.0056* 11.4^2/4.85

F=  0.0056*129.96/4.85

F= 0.727776/4.85

F= 0.15N

Hence the force is 0.15N

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8 t-shirts and 5 pairs of pants cost $220 how much does each t-shirt and pair of pants cost
Yakvenalex [24]
Hey, It looks like you're in Algebra and I'm here to give the best solution I can!

To write the equation, you are going to use the Standard Form. Standard Form is one way of solving this problem, and it is used to find the x,and y-intercepts of a problem.
Standard Form can be written using the equation <span>ax+by=c

</span>In your problem, you will write the equation like so, with 'x' representing T-Shirts, and 'y' representing pants:
<span>
8x+5y=220</span>
Now, in order to find the x-intercept you need to substitute a 0 for the 'y' variable and solve the new equation, 8x=220.
I'm sure you know you need to divide both sides by 8 which will give you the answer x=27.5.

Now, in order to find 'y' you would substitute a 0 for the 'x' variable which will give you an equation that should look like 5y=220.
Then, divided both sides by 5 to get your y-intercept.
y=44

Finally,you know that each T-Shirt (x) is $27.50, and each pair of pants(y)costs $44

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6 0
3 years ago
Solve each equation. #8. 8z = 112
Lynna [10]
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6 0
3 years ago
In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?
Serhud [2]

Option B:

\overline{A B}=\overline{D E}

Solution:

In the given figure \triangle A B C \cong \triangle D E C.

If two triangles are similar, then their corresponding sides and angles are equal.

By CPCTC, in \triangle A B C \ \text{and}\ \triangle D E C,

\overline{AB }=\overline{DE} – – – – (1)

\overline{B C}=\overline{EC} – – – – (2)

\overline{ CA}=\overline{CD} – – – – (3)

\angle ACB=\angle DCE  – – – – (4)

\angle ABC=\angle DEC  – – – – (5)

\angle BAC=\angle EDC  – – – – (6)

Option A: \overline{B C}=\overline{D C}

By CPCTC proved in equation (2) \overline{B C}=\overline{EC}.

Therefore \overline{B C}\neq \overline{D C}. Option A is false.

Option B: \overline{A B}=\overline{D E}

By CPCTC proved in equation (1) \overline{AB }=\overline{DE}.

Therefore Option B is true.

Option C: \angle A C B=\angle D E C

By CPCTC proved in equation (4) \angle ACB=\angle DCE.

Therefore \angle A C B\neq \angle D E C. Option C is false.

Option D: \angle A B C=\angle E D C

By CPCTC proved in equation (5) \angle ABC=\angle DEC.

Therefore \angle A B C\neq \angle E D C. Option D is false.

Hence Option B is the correct answer.

\Rightarrow\overline{A B}=\overline{D E}

5 0
3 years ago
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