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stealth61 [152]
4 years ago
15

Which ionic equation is balanced?

Chemistry
1 answer:
ryzh [129]4 years ago
6 0
For an equation to be balanced, the number of atoms of the reactants and products have to be equal. Therefore, (3) <span>3Fe3++ Al → 3Fe2++ Al3+</span> is the balanced equation, as you have 3 Fe atoms and 1 Al atom on both sides. The exponents are just the charges of the elements, and you don't need to care about these numbers in order to balance a chemical equation.
Hope this would help :))
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What is 8.3 x 10^4 in standard form
Ratling [72]

Answer:

83.000

Step-by-step explanation:

8.3 × 10⁴

= 8.3 × (10 × 10 × 10 × 10)

= 8.3 × (100 × 10 × 10)

= 8.3 × (100 × 100)

= 8.3 × 10.000

= 83.000

Conclusion:

The result of 8.3 × 10⁴ is 83.000

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3 years ago
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Why is DNA called a double helix?
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Explanation:

hope this helps :)

have a nice day !!

7 0
3 years ago
Determine the empirical formula of a compound having the following percent composition by mass: K: 24.74%; Mn: 34.76%; O: 40.50%
Dovator [93]

<u>Answer:</u> The empirical formula of the compound is KMnO_4

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Let the mass of the compound be 100 g

Given values:

% of K = 24.7%

% of Mn = 34.76%

% of O = 40.50%

Mass of K = 24.7 g

Mass of Mn = 34.76 g

Mass of O = 40.50 g

To calculate the empirical formula of a compound, few steps need to be followed:

  • <u>Step 1:</u> Calculating the number of moles of each element

We know:

Molar mass of K = 39.10 g/mol

Molar mass of Mn = 54.94 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of K}=\frac{24.7g}{39.10g/mol}=0.632 mol

\text{Moles of Mn}=\frac{34.76g}{54.94g/mol}=0.633 mol

\text{Moles of O}=\frac{40.50g}{16g/mol}=2.53 mol

  • <u>Step 2:</u> Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 0.632 moles

\text{Mole fraction of K}=\frac{0.632}{0.632}=1

\text{Mole fraction of Mn}=\frac{0.633}{0.632}=1

\text{Mole fraction of O}=\frac{2.53}{0.632}=4

  • <u>Step 3:</u> Writing the mole fraction as the subscripts of each of the element

The empirical formula of the compound becomes K_1Mn_1O_4=KMnO_4

Hence, the empirical formula of the compound is KMnO_4

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Answer:

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Explanation:

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