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wariber [46]
3 years ago
11

When water reacts with potassium metal the hydrogen produced ignites explosively on the surface of water .What cause the ignitio

n
Chemistry
1 answer:
Julli [10]3 years ago
7 0

Answer:

Pottasium reacts with water vigorously and the reation is exothermic. The heat released causes the hydrogen released to ignite

Explanation:

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shtirl [24]
A. Crust B. Mantle C. Outer Core D. Inner Core, i just studied that
5 0
3 years ago
When ammonium nitrate is added to a suspension of magnesium hydroxide in water, the Mg(OH)2 dissolves. Write a net ionic equatio
Viefleur [7K]

Answer:

Net ionic: Mg(OH)_{2}+2NH_{4}^{+}\rightarrow Mg^{2+}+2NH_{3}+2H_{2}O

Explanation:

OH^{-} in Mg(OH)_{2} reacts with NH_{4}^{+} to form NH_{3} and H_{2}O.

Due to this acid-base reaction, Mg(OH)_{2} become soluble whenever NH_{4}NO_{3} is added to suspension of Mg(OH)_{2}.

In this reaction, NH_{4}NO_{3} acts as an acid and Mg(OH)_{2} acts as a base.

Molecular equation: Mg(OH)_{2}+2NH_{4}NO_{3}\rightarrow Mg(NO_{3})_{2}+2NH_{3}+2H_{2}O

Total ionic: Mg(OH)_{2}+2NH_{4}^{+}+2NO_{3}^{-}\rightarrow Mg^{2+}+2NO_{3}^{-}+2NH_{3}+2H_{2}O

Net ionic: Mg(OH)_{2}+2NH_{4}^{+}\rightarrow Mg^{2+}+2NH_{3}+2H_{2}O

7 0
3 years ago
In which of the following reactions will Kc = Kp? a. 4 NH3(g) + 3 O2(g) ⇌ 2 N2(g) + 6 H2O(g) b. SO3(g) + NO(g) ⇌ SO2(g) + NO2(g)
Ratling [72]

Answer:

The correct option is <em>b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)</em>

Explanation:

The relation between Kc and Kp is given by the following equation:

Kp = Kc (RT)^{dn}

where R is the gas constant (0,082 L.atm/K.mol), T is the temperature (in K) and dn is the change in moles.

The change in moles (dn) is calculated as:

dn = moles of products - moles reactants

If dn=0, RT= 1 ⇒ Kc=Kp

We calculate dn for each reaction from the estequiometrial coefficients of products and reactants as follows:

a) 4 NH₃(g) + 3 O₂(g) ⇌ 2 N₂(g) + 6 H₂O(g)

dn= (2+6) - (4+3) = 1 ⇒ Kc ≠ Kp

b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)

dn = (1+1) - (1+1)= 0 ⇒ Kc = Kp

c) 2 N₂(g) + O₂(g) ⇌ 2 N₂O(g)

dn= 2 - (2+1) = -1 ⇒ Kc ≠ Kp

d) 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g)

dn = 2 - (2+1) = -1 ⇒ Kc ≠ Kp

The reaction in which Kc=Kp is b), because reactants and products have the same number of moles.

3 0
3 years ago
Compare Boyle's law, Charles's law, and Avogadro's law. a. What remains constant in each law? b. What are the variables in each
zavuch27 [327]

Answer:

a)

In Boyle's Law, the variable that remains constant is the absolute temperature of the gas.

In Charle's Law, the variable that remains constant is the pressure of the gas.

In Avogadro's Law, the variables that remain constant are pressure and temperature of the gas.

b)

In Boyle's Law, the variables involved are pressure and volume: the law states that for a fixed mass of ideal gas at constant temperature, the pressure of the gas is inversely proportional to the volume:

p\propto \frac{1}{V}

where p is the pressure of the gas and V the volume.

In Charle's Law, the variables involved are volume and temperature: the law states that for a  fixed mass of ideal gas at constant pressure, the volume of the gas is directly proportional to the temperature:

V\propto T

where V is the volume of the gas and T the temperature.

In Avogadro's Law, the variables involved are the volume and the number of moles: the law states that for an ideal gas kept at constant pressure and temperature, the volume of the gas is directly proportional to the number of moles:

V\propto n

Where V is the volume of the gas and n the number of moles.

c)

See the graphs of the three Laws in attachment:

- First graph: Boyle's Law, which shows that the pressure of the gas is inversely proportional to the volume

- Second Graph: Charle's Law, which shows that the volume of the gas is directly proportional to the absolute temperature

- Third graph: Avogadro's Law, which shows that the volume of the gas is directly proportional to the number of moles of the gas

d)

Here we want to re-write the three laws by making V the subject.

For Boyle's law, we get:

V\propto \frac{1}{p}

For Charle's Law, we get:

V\propto T

For Avogadro's Law, we get:

V\propto n

Therefore, we see that the two laws that show a direct proportionality are Charle's Law and Avogadro's Law, while Boyle's Law shows an inverse proportionality between the two variables.

8 0
4 years ago
What type of bond allows heat and electricity to move freely throughout the material?
OLga [1]

That would be an ionic bond since it has electrons to spare, rather than a convalent bond where all the electrons are taken up thus it is not a good conductor

8 0
3 years ago
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