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ExtremeBDS [4]
3 years ago
12

Consider 1-bromopropane (CH3CH2CH2Br) (a) Draw a Newman projection for the conformation in which !CH3 and !Br are anti (dihedral

angle 1808). (b) Draw Newman projections for the conformations in which !CH3 and !Br are gauche (dihedral angles 608 and 3008). (c) Which of these is the lowest energy conformation? (d) Which of these conformations, if any, are related by reflection?

Chemistry
1 answer:
KiRa [710]3 years ago
6 0

Answer:

<em>Figure Attached</em>

Explanation:

a. To draw a Newman projection we draw a circle for the rare carbon and and put a dot in center of circle for the front carbon. For a dihedral angle of 180° we put the respective groups opposite to each other making an angle of 180°.

b. For a dihedral angle of 60° Just rotate the conformation of dihedral angle 180° to anti clock wise up to 120°.  

For a dihedral angle of 300° Just rotate the conformation of dihedral angle 180° to clock wise up to 120°.  

c. The lowest energy conformation is the conformation having dihedral angle 180°. Because in this conformation the bulky groups are anti to each other.

d. Conformations having dihedral angle  60° and 300° are reflection of each other.

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Picture this in your mind as you read it: You weigh an empty, clean, dry beaker on the balance (scale). It weighs 32.15 grams. Y
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Answer:

2.25 g

Explanation:

The mass of the solid X must be the total mass (beaker + solid X) less than the mass of the beaker. Then:

mass of the solid X = 34.40 - 32.15

mass of the solid X = 2.25 g

The difference of 0.25 g must occur for several problems: an incorrect weight in the balance, the configuration of the balance, the solid can be hydrophilic and absorbs water, and others.

6 0
3 years ago
A sample of gallium Bromide GaBr2,weighing 0.165 g was dissolved in water and treated with silver nitrate AgNO3, and resulting t
tresset_1 [31]

<u>Answer:</u> The percent gallium in gallium bromide is 30.30 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of gallium bromide = 0.165 g

Molar mass of titanium gallium bromide = 229.53 g/mol

Putting values in equation 1, we get:

\text{Moles of gallium bromide}=\frac{0.165g}{229.53g/mol}=0.00072mol

  • The chemical equation for the reaction of gallium bromide and silver nitrate follows:

GaBr_2+2AgNO_3\rightarrow 2AgBr(s)+Ga(NO_3)_2

By Stoichiometry of the reaction:

1 moles of gallium bromide produces 1 mole of gallium nitrate

So, 0.00072 moles of gallium bromide will produce = \frac{1}{1}\times 0.00072=0.00072moles of gallium nitrate

  • Now, calculating the mass of gallium nitrate from equation 1, we get:

Molar mass of gallium nitrate = 193.73 g/mol

Moles of gallium nitrate = 0.00072 moles

Putting values in equation 1, we get:

0.00072mol=\frac{\text{Mass of gallium nitrate}}{193.73g/mol}\\\\\text{Mass of gallium nitrate}=0.139g

Calculating the mass of gallium in the reaction, we use unitary method:

In 1 mole of gallium nitrate, 1 mole of gallium atom is present.

In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.

So, in 0.139 grams of gallium nitrate, the mass of gallium present will be = \frac{69.72}{193.73}\times 0.139=g

  • To calculate the percentage composition of gallium in gallium bromide, we use the equation:

\%\text{ composition of gallium}=\frac{\text{Mass of gallium}}{\text{Mass of gallium bromide}}\times 100

Mass of gallium bromide = 0.165 g

Mass of gallium = 0.050 g

Putting values in above equation, we get:

\%\text{ composition of gallium}=\frac{0.050g}{0.165g}\times 100=30.30\%

Hence, the percent gallium in gallium bromide is 30.30 %.

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