1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maru [420]
3 years ago
6

How many grams of carbon are in 1.000mole of carbon?

Chemistry
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

one mole of carbon would have a mass of 12.011 grams

NNADVOKAT [17]3 years ago
3 0

Answer:

One mole of Carbon would have a mass of 12.011 grams.

Explanation:

I hope I helped! :)

You might be interested in
PLEASE HELP ME YOU DONT HAVE TO DO WORK JUST TELL ME IF ITS RIGHT ON THE ORGANIC AND INORGANIC SIDE PLEASEE
Fittoniya [83]

Answer:

Its right you dont have to change anything

3 0
3 years ago
Calculate the density of an object with a mass of 30g and volume of 6cm^3
Kipish [7]
Density = Mass ÷ Volume

D= 30g ÷ 6 cm^3

D= 5 g/dm^3

3 0
3 years ago
Which of the following instrument would you use to see a plant cell?
Gemiola [76]
B . microscope
this is the answer .
3 0
2 years ago
Read 2 more answers
HELP PLEASE THE OTHER 'ANSWER' ISNT EVEN AN ANSWER!
hodyreva [135]

Answer:

most likely that (2) the replicated experiment was performed incorrectly.

Why, u ask? u dare question me:

1- The initial experiment invalidness cannot be proven.

2- <em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>s</u></em><em><u>e</u></em><em><u>c</u></em><em><u>o</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>s</u></em><em><u>w</u></em><em><u>e</u></em><em><u>r</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>c</u></em><em><u>o</u></em><em><u>r</u></em><em><u>r</u></em><em><u>e</u></em><em><u>c</u></em><em><u>t</u></em>

3- Different labaratories does not effect the outcome, as long as the parameter and environment of the replicated experiment is the same as when the initial experiment was conducted.

4- Already knowing the data and errors would increase the precision of the replicated experiment.

5- Change in variables should still be in the objective (or purpose) of the experiment, thus, major difference in the outcome should not happen.

happy learning!

4 0
3 years ago
How to determine how many valence electrons an element has?
In-s [12.5K]
Usually (ignoring transition metals, as they kinda get trickier), the element's valency can be found out by its group (column) number. Usually, we ignore the transition metal block while counting these columns, so Aluminium is in group 3, for example. Since Aluminium is in group 3, it has 3 valence electrons.
8 0
3 years ago
Other questions:
  • What is the relationship between the concentration of particles in a solution and the solution’s vapor pressure? As solute conce
    8·2 answers
  • What common household element can, over time, reduce airflow, insulate components, reduce heat exchange or even cause the system
    13·2 answers
  • Solid calcium oxide reacts with sulfur trioxide gas to produce solid calcium sulfate
    7·1 answer
  • What kind of chemical reaction does the chemical equation sodium + chlorine → sodium chloride represent?
    10·2 answers
  • A student is asked to balance an equation by using the half-reaction method. He determines the two half reactions as shown below
    7·1 answer
  • A gas that has a volume of 28 Liters, a Temperature of 318 K, and an unknown pressure initially
    7·1 answer
  • A 1M solution is made of each item in a pair. When would this combination create a buffer? Chose the pairs below that you could
    5·1 answer
  • I'll give brianliest if correct .
    5·1 answer
  • Identify the acid and conjugate base pair in the following equation:
    15·1 answer
  • 27). How many feet per second is a wave going if it travels a distance of one mile in 7.35 seconds?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!