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zloy xaker [14]
3 years ago
15

How are exponents and logarithms related? give an example with you explanation

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0
Exponents and logarithms are inverse functions, which means that exponents are the way to "undo" logarithms and logarithms are what you use to "undo" exponents. exponents tell you how many times you have to multiply a value and logarithms ask which exponent you need to use to get a specified value. exponential equations are used in a lot of scientific fields; for example, in biology, they're used to calculate the half-life of organisms. they can also be used to estimate the growth of a population. additionally, the richter scale, which measures the magnitude of earthquakes, uses logarithms.
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Solve the system of equations by substitution <br><br> y = 2x + 1 and 3x + y = 16
Luden [163]

Answer:  y=7,x=3

Steps:

y = 2x + 1

3x + y = 16

Substitute y = 2x + 1

3x + 2x + 1 = 16

Simplify

5x+1=16

Isolate x for 5x + 1 = 16: x = 3

For y = 2x + 1

Substitute x = 3

y = 2 · 3 + 1

Simplify

y = 7

The solutions to the system of equations are:

y = 7, x = 3

Hope This Helps!

6 0
3 years ago
PLEASE HELP!
Nadya [2.5K]

Answer: no solution or zero solutions.

Step-by-step explanation:

8 0
3 years ago
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Marta_Voda [28]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Given the functions f(x) = 2x + 5 and g(x) = x2 + 8, which of the following functions represents f(g(x)] correctly?
lakkis [162]

Answer:

Choice 4.

Step-by-step explanation:

f(g(x))

Replace g(x) with x^2+8 since g(x)=x^2+8.

f(g(x))

f(x^2+8)

Replace old input,x, in f with new input, (x^2+8).

f(g(x))

f(x^2+8)

2(x^2+8)+5

Distribute:

f(g(x))

f(x^2+8)

2(x^2+8)+5

2x^2+16+5

Combine like terms:

f(g(x))

f(x^2+8)

2(x^2+8)+5

2x^2+16+5

2x^2+21

7 0
3 years ago
An extremely large sink hole has opened up in a field just outside of the city limits. It is difficult to measure across the sin
abruzzese [7]
Triangle ABC and triangle DCE are congruent, so line DE = line AB

Use the cosine rule to find angle ACB
52.2^{2}= 50^{2}+  70^{2}-(2*50*70*cos(ACB))
2724.84=7400-(7000cos(ACB))
2724.84-7400=-7000cos(ACB)
-4675.16=-7000cos(ACB)
\frac{4675.16}{7000}=cos(ACB)
Angle ACB= cos^{-1} ( \frac{4675.16}{7000})
Angle ACB = 48.1°

5 0
3 years ago
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