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3 years ago

Is anyone good with probability? I need help with Allyson’s and brittney’s solution.

Mathematics

1 answer:

garri49 [273]3 years ago

4 0

Answer:

a) 80%

80/100 *100 = 80%

b) 10 %

Sorry not able to draw a venn diagram

smartphone 50

both 30

tablet 10

10 people 10/100 *100 = 10%

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What is the distance between (–4, –10) and (–4, –4)?

Gre4nikov [31]

Answer:

6 units

Step-by-step explanation:

(-4 , -10) ; (-4 , -4)

Distance = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

$= \sqrt{(-4-[-4])^{2}+(-4-[-10])^{2}}\\\\= \sqrt{(-4+4)^{2}+(-4+10)^{2}}\\\\=\sqrt{0+(6)^{2}}\\\\= \sqrt{36}\\\\= 6$

4 0

3 years ago

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TRUE OF FALSE : -4 <-2

Licemer1 [7]

Answer: false but not sure

6 0

3 years ago

Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

tankabanditka [31]

Answer:

The option " The sum has degree of 6 , but the difference has a degree of 7 " is correct.

Step-by-step explanation:

Given that the sum and difference of the polynomials $3x^5y-2x^3y^4-7xy^3$ and $-8x^5y+2x^3y^4+xy^3$

<h3>Now sum the given polynomials :</h3>

$3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)$

$=3x^5y-2x^3y^4-7xy^3-8x^5y+2x^3y^4+xy^3$

$=-5x^5y+0-6xy^3$

$=-5x^5y-6xy^3$

Therefore $3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)=-5x^5y-6xy^3$

In the simplified <u>sum of the polynomials</u> $-5x^5y-6xy^3$ we have <u>the degree is 6</u>

<h3>Now difference the polynomials </h3>

$3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)$

$=3x^5y-2x^3y^4-7xy^3+8x^5y-2x^3y^4-xy^3$

$=11x^5y-4x^3y^4-8xy^3$

Therefore $3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)=11x^5y-4x^3y^4-8xy^3$

In the simplified <u>difference of polynomials</u> $11x^5y-4x^3y^4-8xy^3$ we have <u>the degree is 7</u>

Therefore the option " The sum has degree of 6 , but the difference has a degree of 7 " is correct

6 0

3 years ago

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Living with parents: The Pew Research Center reported that 36% of American Millennials (adults ages 18-31) stll live at home wit

Lera25 [3.4K]

Answer:

$\mathbf{The \ sample \ comes \ from \ a \ population \ of \ Millennial \ students }$ $\mathbf{at \ their \ campus\ where \ 3 6\%\ still\ live\ at\ home\ with\ their \ parents}$

Step-by-step explanation:

From the given information.

The proportion of American Millennials still with their parents = 0.36

The sample size = 300

Sample proportion = 0.43

Level of significance = 0.006

P-value = 0.006

Null hypothesis:

$\mathbf{H_o: Of \ Millennial \ students \ at \ their \ campus, \ 36\% \ }$ $\mathbf{ live \ at \ some \ with \ their \ parents . }$

$\mathbf{H_a: More \ than \ 36\% \ of \ Millennial \ students \ at \ their \ campus \ live \ at \ home }$ $\mathbf{ \ with \ their \ parents}$

The required task is to determine the assumption about the sample that underlies the hypothesis test from the given options.

$\mathbf{The \ sample \ comes \ from \ a \ population \ of \ Millennial \ students }$ $\mathbf{at \ their \ campus\ where \ 3 6\%\ still\ live\ at\ home\ with\ their \ parents}$

This is because the student wants to check if the null hypothesis ( which states that of Millennial students at their campus, 36% live at home with their parents) is correct or not.

7 0

3 years ago

5x + 6y = 18 and 18x -15y =36

stira [4]

5x+6y=18

5x=18-6y

x=(18-6y)/5

Use that in the other equation
18(18-6y)/5 - 15y = 36

64.8-21.6y - 15y = 36

28.8=36.6y
.7868=y

Now put that number in for y on the first equation

5x+6(.78) = 18
5x + 4.68 = 18
5x = 13.32
x = 2.66
and y = .78

4 0

4 years ago

Read 2 more answers