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3 years ago

State TWO (2) examples of continuous random variable.

Mathematics

1 answer:

Contact [7]3 years ago

5 0

Answer:

example 1 :

a number of patients in doctor surgery

example 2:

a number of children in a family

<h3>Request:</h3>

if it help full please mark as brain list

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Find the multiplicative inverse of 2/3 * - 5/7

boyakko [2]

Answer:

$-\frac{21}{10}$ is the required multiplicative inverse.

Step-by-step explanation:

First of all simplify the given expression.

$\frac{2}{3}\cdot \frac{-5}{7}=-\frac{2\cdot \:5}{3\cdot \:7}=-\frac{10}{21}$

Multiplicative inverse of any number when multiplied gives 1.

The multiplicative inverse of $-\frac{10}{21}$ is $-\frac{21}{10}$ because:

$-\frac{10}{21}\times -\frac{21}{10}=1$

Best Regards!

6 0

3 years ago

The rate of change in sales for Garmin from 2008 through 2013 can be modeled by

Zina [86]

Answer:

a) The model for the sales of Garmin is represented by $S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + 47.112$ .

b) The average sales of Garmin from 2008 through 2013 were $ 2.5 billion.

Step-by-step explanation:

a) The model for the sales of Garmin is obtained by integration:

$S(t) = -0.0972\int {t^{2}} \, dt + 2.136\int {t}\,dt -11.9 \int\,dt$

$S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + C$ (1)

Where $C$ is the integration constant.

If we know that $t = 9$ and $S(t) = 2.9$ , then the model for the sales of Garmin is:

$-\frac{81}{2500} \cdot 9^{3} + \frac{267}{250}\cdot 9^{2}-11.9\cdot (9) + C = 2.9$

$C = 47.112$

The model for the sales of Garmin is represented by $S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + 47.112$ .

b) The average sales of the Garmin from 2008 through 2013 ( $\bar{S}$ ) is determined by the integral form of the definition of average, this is:

$\bar{S} = \frac{1}{13 - 8} \cdot \int\limits^{13}_{8} {S(t)} \, dt$ (2)

$\bar S = \frac{1}{5}\cdot \int\limits^{13}_{8} {\left[-\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2}-11.9\cdot t + 47.112 \right]} \, dt$

$\bar S = \frac{1}{5}\cdot \left[-\frac{81}{10000}\cdot (13^{4}-8^{4}) +\frac{89}{250}\cdot (13^{3}-8^{3}) -\frac{119}{20}\cdot (13^{2}-8^{2}) +47.112\cdot (13-8) \right]$ $\bar{S} = \frac{1}{5}\cdot (-198.167+599.86-624.75+235.56)$

$\bar{S} = 2.5$

The average sales of Garmin from 2008 through 2013 were $ 2.5 billion.

7 0

3 years ago

Sara claims that the number of pages she has read in her book is proportional to the number of minutes that she has spent readin

nikitadnepr [17]

X = 77.789
y = 23...............................

4 0

3 years ago

Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)

melamori03 [73]

Answer:

Step-by-step explanation:

Given that:

$f_x = \dfrac{x^2}{a^7-x^7}$

$= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}$

$= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}$

since $\Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)$

Then, it implies that:

$\implies \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}$

$\mathbf{= \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}$

7 0

3 years ago

Guys I need help, this is so important for my grade

Dmitrij [34]

Answer:

For Part C) use numbers 1 2 3 4.

Step-by-step explanation:

8 0

3 years ago