5/d^-3. rewrite so its a positive exponent. the answer is 5d^3 but idk why.

Which number is the additive inverse of 47? Hi. SI56 -47 1 W om 04

Anvisha [2.4K]

Answer:

4 $\frac{1}{4}$

Step-by-step explanation:

The additive inverse is the value that must be added to the number to give zero.

- 4 $\frac{1}{4}$ + 4 $\frac{1}{4}$ = 0

↑ additive inverse

5 0

2 years ago

Zero and negative exponentswrite in simplest for without zero or negative exponents- 17 ⁰

Valentin [98]

$-17^0=(-17)^0=1$ $\begin{gathered} (-2)^2\times(-2)^{-5}=(-2)^{2-5} \\ =(-2)^{-3} \\ =\frac{1}{(-2)^3} \\ =\frac{1}{-8} \end{gathered}$

Thus, the final answers are 1 and -1/8.

4 0

11 months ago

Tom went to a shop where there was a 20% off sale taking place

-Dominant- [34]

Find 20 percent of $20 by multiplying 0.20 x20

You get $4. That’s what he saved.

7 0

2 years ago

30 points and brainliest help me out please. 5th grade

Tatiana [17]

Answer:

Step-by-step explanation:

a,a, and a

8 0

3 years ago

A professor receives, on average, 24.7 emails from students the day before the midterm exam. To compute the probability of recei

MaRussiya [10]

Answer:

Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is $X \sim Poisson(\lambda=24.7)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

The best answer for this case would be:

C. Poisson distribution

Step-by-step explanation:

Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is $X \sim Poisson(\lambda=24.7)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$