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SVEN [57.7K]
3 years ago
12

6. What is the coordinates of the center and the radius of the circle

Mathematics
2 answers:
Alina [70]3 years ago
6 0

Answer: Center:(4,3)

Radius:5

Step-by-step explanation: Happy yo help :)

PtichkaEL [24]3 years ago
3 0

Answer:

A. Center (4,3); Radius = 5 units

Step-by-step explanation:

The equation of a circle can be written in the form

(x-h)^2 + (y - k)^2 = r^2

where (h,k) is the center and r is the radius

(x-4)^2 + (y - 3)^2 = 25

(x-4)^2 + (y - 3)^2 = 5^2

The center is (4,3) and the radius is 5

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The coordinate grid shows points A through K. What point is a solution to the system of inequalities? y ≤ −2x + 10 y > 1 over
vlabodo [156]

Answer:

A, C, D and K

Step-by-step explanation:

First, plot the solution set to the system of two inequalities.

The inequality y\le -2x+10 determines solid line and bottom shaded region under this line.

The inequality y>\dfrac{1}{2}x-2 determines dotted line and top shaded region under this line.

The intersection of these two regions is the solution set to the system of two inequalities.

Points A, C, D and K belong to this region.

4 0
2 years ago
Solve the equation using the Zero­Product Property. 6x(3x + 1) = 0
neonofarm [45]
   
\displaystyle  \\ 
6x(3x + 1) = 0 \\  \\ 
\Longrightarrow ~~ 6x = 0~~\texttt{or}~~3x+1=0 \\  \\ 
6x = 0 ~~\Longrightarrow ~~ x_1 =  \frac{0}{6} = \boxed{0} \\  \\ 
3x+1 = 0 ~~\Longrightarrow ~~ 3x = -1  ~~\Longrightarrow ~~ x_2 =  \frac{-1}{3} = \boxed{-\frac{1}{3}} \\  \\



4 0
3 years ago
1. Factor the expression using the two different techniques listed for Parts 1(a) and 1(b).
Bond [772]

Answer:

1. Factor the expression using the two different techniques listed for Parts 1(a) and 1(b).

(a) Factor the given expression using the GCF monomial.

(b) Factor the given expression using the difference of squares.

DO NOT ANSWER UNLESS YOU CAN EXPLAIN THIS TO ME CORRECTLY

3 0
2 years ago
At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]
denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

f(x) = x^3-2x^2-4x+1 in the interval  [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

f(1) = 1-2-4+1 = -4\\f(0) = 1

The value

\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5

Find derivative for f

f'(x) = 3x^2-4x-4

Equate this to -5 to check mean value theorem

3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1

We find that 1/3 lies inside the interval (0,1)

4 0
2 years ago
What is the answer to this​
Alborosie
The answer to the question is b

$9 each hour she works + 7.50 fee
$7.50+$9h= $34.50
7 0
3 years ago
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