Answer:
third option
Step-by-step explanation:
-- On a flat, 2-dimensional (x-y) graph, the locus of all points that are
4mm from a given line consists of two more lines, one on each side
of the given line, and all three lines are parallel.
-- If we want to talk about 3-dimensional space, then the locus of all
points that are 4mm from a given line is a cylinder, with radius of 8mm,
and the given line is the axis of the cylinder.
2 ounce bag will cost less than $1.25
6 ounces ÷ 3 = 2 ounces
$3.60 ÷ 3 = $1.20
OR
$3.60 ÷ 6 ounces = $0.60 per ounce
2 ounces = $ 0.60 × 2 = $1.20
Step-by-step explanation:
First let fully expand this equation
Use the product of squares method.
![(x - y) {}^{2} = {x}^{2} - 2xy + {y}^{2}](https://tex.z-dn.net/?f=%28x%20-%20y%29%20%7B%7D%5E%7B2%7D%20%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%20-%202xy%20%2B%20%20%7By%7D%5E%7B2%7D%20)
![x {}^{2} - 6x + 9](https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20-%206x%20%20%2B%209)
Add like terms
![{x}^{2} - 6x - 40](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20-%2040)
First, let find the vertex.
![- \frac{b}{2a}](https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7Bb%7D%7B2a%7D%20)
![\frac{6}{2} = 3](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B2%7D%20%20%3D%203)
Plug this in to find the minimum point.
![{3}^{2} - 6(3) - 40 = - 49](https://tex.z-dn.net/?f=%20%7B3%7D%5E%7B2%7D%20%20-%206%283%29%20-%2040%20%3D%20%20-%2049)
So the minimum point is at (3,49).
Now we can find some zeroes.
Apply AC Method.
![(x - 10)(x + 4)](https://tex.z-dn.net/?f=%28x%20-%2010%29%28x%20%2B%204%29)
Solve each equation for zero.
![x = 10](https://tex.z-dn.net/?f=x%20%20%3D%2010)
![x = - 4](https://tex.z-dn.net/?f=x%20%3D%20%20-%204)
So Graph points
(3,49)
(-4,0)
(10,0)
A bouncing ball issue reaches its next peak as some fraction or multiple of the previous peak, so, that'd make it a
geometric sequence.
so, let's take a peek, 27, 18, 12
now, to get the
common factor from a geometric sequence, since it's just a multiplier, if you divide any of the terms by the term before it, the quotient is then the common factor, let's do so with hmm say 12 and 18, 12/18 = 2/3 <---- the common factor, you can check if you so wish with 18/27.
and the first term is of course, 27.