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3 years ago

Can u help me plz its vocabulary

Mathematics

2 answers:

Masja [62]3 years ago

8 0

UM HAD THE RIGHT ANSWER SO LISTEN TO HER

jeka57 [31]3 years ago

6 0

Answer:

Q- acute

R- right

S-acute

- QRS is a right triangle because it has a small square at the right angle.

hope this helps!

Step-by-step explanation:

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X + y = -3 & 5x - 2y = -50 ELIMINATION

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3 years ago

PLEASE HELP ME rename 8 ten thousands 4 hundreds

Naddik [55]

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As John walks 16 ft towards a chimney, the angle of elevation from his eye to the top of the chimney changes from 30° to 45°. Id

levacccp [35]

ANSWER

The height is $22ft$

EXPLANATION

Let the height of the chimney be x.

$\tan(45 \degree) = \frac{x}{y}$

$1 = \frac{x}{y}$

$x = y$

$\tan(30 \degree) = \frac{x}{16+ y}$

$\frac{ \sqrt{3} }{3} = \frac{x}{16 + y}$

Cross multiply

$\sqrt{3} (16 + y) = 3x$

$16 \sqrt{3} + y \sqrt{3} = 3x$

Put

$y = x$

into the equation;

$16 \sqrt{3} + x \sqrt{3} = 3x$

Group similar terms:

$16 \sqrt{3}= 3x - x \sqrt{3}$

$16 \sqrt{3}= (3 - \sqrt{3})x$

$\frac{16 \sqrt{3} }{3 - \sqrt{3} } = x$

$x=21.856$

The height of the chimney to the nearest feet is 22

6 0

3 years ago

The original line has the equation of y=-2x+8

enot [183]

The new equation of line that is perpendicular to the original that goes through the point (6, -1) in slope intercept form is $y = \frac{1}{2}x - 4$

<h3>Solution:</h3>

Given that original line has the equation of y = -2x + 8

We have to write a new equation that is perpendicular to the original that goes through the point (6, -1)

Let us first find slope of original line

The slope intercept form of line is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form and given original equation, we get "m = -2"

Thus slope of original line "m" = -2

We know that product of slope of a line and slope of line perpendicular to it are always -1

slope of original line x slope of line perpendicular to it = -1

$\begin{array}{l}{-2 \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{1}{2}}\end{array}$

Let us find equation of line with slope m = 1/2 and passes through point (6, - 1)

Substitute $m = \frac{1}{2}$ and (x, y) = (6, -1) in eqn 1

$-1 = \frac{1}{2} \times 6 + c\\\\-1 = 3 + c\\\\c = -4$

Thus the required equation of line is:

Substitute "c" = -4 and $m = \frac{1}{2}$ in eqn 1

$y = \frac{1}{2}x - 4$

Thus the equation of line perpendicular to original line is found

7 0

3 years ago

Can u help me plz its vocabulary​

Can u help me plz its vocabulary