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Nonamiya [84]
3 years ago
7

Solve 4sin^2 x-3=0 find two values of sinx that satisfy this equation

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0
4 sin^{2} x-3=0 \\ 4 sin^{2} x=3 \\  sin^{2} x= \frac{3}{4}  \\ sinx= \pm \sqrt{ \frac{3}{4} }  \\ sinx= \frac{ \sqrt{3} }{2}  \ or \ sinx=- \frac{ \sqrt{3} }{2}  \\ x=  \frac{ \pi }{3} , \  \frac{2 \pi }{3} , \  \frac{4 \pi }{3} , \  \frac{5 \pi }{3}
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