Question

Solve 4sin^2 x-3=0 find two values of sinx that satisfy this equation

Answer 1

$4 sin^{2} x-3=0 \\ 4 sin^{2} x=3 \\ sin^{2} x= \frac{3}{4} \\ sinx= \pm \sqrt{ \frac{3}{4} } \\ sinx= \frac{ \sqrt{3} }{2} \ or \ sinx=- \frac{ \sqrt{3} }{2} \\ x= \frac{ \pi }{3} , \ \frac{2 \pi }{3} , \ \frac{4 \pi }{3} , \ \frac{5 \pi }{3}$