Arrange these numbers from least to greatest

F(x) = ( - 3x² + 2 – 2)e". Find f'(x) and f''(x).<br> f'(2) =<br> f''(c)<br> =

prisoha [69]

Answer:

-3x²-5xeˣ-eˣ

-3eˣx²-11eˣx-6eˣ

Step-by-step explanation:

I'm going to go by the picture and not what you wrote in your title.

To find the derivative of this we have to apply the product rule

(a*b)'=

a'*b+a*b'

We plug in our numbers and get

(-3x²+x-2)'*eˣ+(-3x²+x-2)*eˣ'

Now we can evaluate the derivatives and simplify

(-3x²+x-2)'= -6x+1

eˣ'=eˣ

which means we have

(-6x+1)*eˣ+(-3x²+x-2)*eˣ

Simplify

-6xeˣ+eˣ-3x²eˣ+xeˣ-2eˣ

Combine like terms

-3x²eˣ-5xeˣ-eˣ

Now we just need to find the derivative of this

We can apply the same product rule as we did before

(-3x²eˣ)'

Let's start by factoring out the -3 to get

-3(x²eˣ)'

which is equal to

-3(x²eˣ'+x²'eˣ)

Compute this and get

-3(x²eˣ+2xeˣ)= -3x²eˣ-6xeˣ

Now let's find the derivative of the second part

(-5xeˣ)'

-5(x'eˣ+xeˣ')

-5(eˣ+xeˣ)

-5eˣ-5xeˣ

Which means we have

(-3x²eˣ-6xeˣ)+(-5eˣ-5xeˣ)-eˣ

Combine like terms and get

-3eˣx²-11eˣx-6eˣ

3 0

3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

Which equation matches the hanger diagram? <br> pls help !!!

telo118 [61]

The answer is D

Because there are two x’s

And 5 number 1’s

So 2x=5

6 0

2 years ago

Read 2 more answers

A side of the triangle below has been extended to form an exterior angle of 132°. Find the value of X

Zinaida [17]

Answer:

x = 114°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, thus

x + 18° = 132° ( subtract 18° from both sides )

x = 114°

7 0

2 years ago

PLZ HLP Given the equation 5x + y = 7, which equation below would cause a consistent-independent system?

DanielleElmas [232]

Answer:

the equation D ) would cause a consistent-independent system.

Step-by-step explanation:

A ) 5 x + y = 7 /*( -2 )

10 x + 2 y = 14

--------------------

- 10 x - 2 y = - 14

10 x + 2 y = 14

------------------------

0 x = 0 ( Dependent system )

B ) 5 x + y = 7 / * 3

- 15 x - 3 y = - 6

--------------------------

15 x + 3 y = 21

- 15 x - 3 y = - 6

-------------------------

0 x = 15 ( Inconsistent system )

C ) 5 x + y = 7

5 x + y = - 7 / * ( - 1 )

---------------------------

5 x + y = 7

- 5 x - y = 7

------------------

0 x = 14 ( Inconsistent system )

D ) 5 x + y = 7 / * ( - 2 )

6 x + 2 y = 7

------------------

- 10 x - 2 y = - 14

6 x + 2 y = 7

-----------------------

- 4 x = - 7; x = 7/4; y = - 7/4

7 0

2 years ago