Answer:
Option C is right
Step-by-step explanation:
Given are two samples
I group has sample size 90, mean = 9.2 and std dev =0,.37
II group has sample size 70, mean = 7.3 and std dev = 0.58
we find that mean difference i.e. difference between mean hours of sleep between two groups
= 9.2-7.3 = 1.9
Std error for difference = 0.0620
Since sample size is sufficiently large we can use Z critical for 99%
i.e. 2.58
Margin of error =±2.58(0.062)
=0.16
Hence confidence interval 99% for difference in hours of sleep
= (1.9-0.16,1.9+0.16)
=(1.74, 2.06)
Answer:
7-2x
Step-by-step explanation:
Move the expresion without change the signs of each numbers.
Check the picture below.
make sure your calculator is in Degree mode.
Answer: C= -10
Step-by-step explanation: First step: simplify both sides of the equation
3c−2(c+10)=7c−5(c+2)
3c+(−2)(c)+(−2)(10)=7c+(−5)(c)+(−5)(2) (Distribute)
3c+−2c+−20=7c+−5c+−10
(3c+−2c)+(−20)=(7c+−5c)+(−10) (Combine Like Terms)
c + -20 = 2c - 10
c - 20 = 2c - 10
Step 2: Subtract 2c from both sides
c - 20 - 2c = 2c -10 - 2c
−c−20=−10
Step 3: Add 20 to both sides
−c−20+20=−10+20
−c=10
Step 4: Divide both sides by -1
-c/-1 = 10/-1
C=-10