Answer: 1, 2, 4 are accurate.
Explanation:
1. Joe is on a hill (on a trail) above the ocean. The beach and ocean are at similar altitudes. Therefore Joe is at a higher altitude than if he was at the beach.
2. Since Joe is on a hill, he has a higher altitude than at sea level. Air at a higher altitude has lower density because there is less air "ontop" of itself than at lower altitudes. As well, his hill is above the ocean, which means there is a lot of water, making the air more humid than where he is. Humidity also makes air denser.
4.The air pressure will decrease if Joe goes up to higher altitudes because there will be less air on top of itself.
Answer:
The diagram is attached below.
Explanation:
when sodium and chlorine comes close together they form anion and cation. The compound formed is called sodium chloride.
Both atoms bonded together through ionic bond.
Ionic bond:
It is the bond which is formed by the transfer of electron from one atom to the atom of another element.
Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.
For example:
Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.
Answer:
Chemical energy stored in glucose
Explanation:
Answer:
The correct answer is option D.
Explanation:
In the presence of SDS single band appeared, while in the absence of SDS two bands appeared. SDS or sodium dodecyl sulfate refers to an anionic detergent, which combines with amino acid side chains providing the protein a net negative charge. It dissociates the non-covalent bonds.
In SDS-PAGE, the separation of proteins takes place on the basis of their molecular weight. Options A and B are incorrect as only in the presence of SDS, the separation of protein subunits takes place. Option C is also incorrect as a protein containing distinct molecular weight cannot show single band.
Option D is correct as the presence of SDS supplements a bunch of negative charges to the protein, thus, charge is not the factor. Therefore, the proteins are distinguished on the basis of the molecular weight. Thus, identical molecular weight demonstrates a single band. In the non-presence of SDS, charge performs a function along with the molecular weight, therefore, two bands appear.
