Explanation:
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Answer:-3463 kJ and -3452kJ
Explanation:
ΔU is the change in internal energy of a system and its formula is;
ΔU = q + w
Where q represents heat transferred into or out of the system. Its value is positive when heat is transfer into the system and negative when heat is produced by the system.
W represents the work done on or by the system. Its value is positive when work is done on the system and negative when it is done by the system.
For the system in this question, we see that it produces heat which means heat is transferred out of the system, therefore the value of q is negative, it can also be seen that work is done by the system which means that w is also negative.
Therefore,
ΔU = -q-w
ΔU = -3452 kJ – 11kJ
= - 3463kJ
ΔH is the change in the enthalpy of a system and its formuls is;
ΔH = ΔU + Δ(PV)
By product rule Δ(PV) becomes ΔPV + PΔV
At constant pressure ΔP = 0. Therefore,
ΔH = -q-w + PΔV
w is equals to PΔV, So:
ΔH = -q
ΔH = -3452kJ
Answer:
It means your dad is making those chickens cannibal's.......
Explanation:
Answer:
-7.66 x 10^-5 mol/L per second.
Explanation:
You find the avg. rate of decomposition by finding the overall amount of matter decomposed and dividing it by the time the mixture/substance decomposed for. In this case, it would be (0.1054 mol/L - 0.1103 mol/L ) / 64.0 s.
This gives you -0.0000766 mol/L per second (using significant figures rules), or -7.66 x 10^-5 mol/L per second.
Cheers.
