Answer:
Options: A, B, and C correctly solve for x.
Step-by-step explanation:
A).
= ![\frac{15}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B2%7D)
Multiplying both sides by 2 gives;
5x = 15
x = 15 ÷ 5 = 3
∴ This option correctly solve for x.
B).
x +
= 7
x = 7 -
= ![\frac{14}{2} -\frac{7}{2} = \frac{7}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B2%7D%20-%5Cfrac%7B7%7D%7B2%7D%20%3D%20%5Cfrac%7B7%7D%7B2%7D)
∴ This option correctly solve for x.
C).
x + 3 = ![\frac{21}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B5%7D)
x = ![\frac{21}{5} - \frac{15}{5} = \frac{6}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B5%7D%20-%20%5Cfrac%7B15%7D%7B5%7D%20%20%3D%20%5Cfrac%7B6%7D%7B5%7D)
But the option give x as 5/6 hence this option does not correctly solve for x.
D).
5x = 11/2
x = 11/2 ÷ 5 = 11/2 × 1/5 = 11/10
But the option gives x as 10/11 so it does not correctly solve for x.
Answer:
c. ![3x+1](https://tex.z-dn.net/?f=3x%2B1)
Step-by-step explanation:
Since the divisor is in the form of
, use what is called Synthetic Division. Remember, in this formula, <em>-c</em> gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 3 −11 −4
↓ 12 4
_______________
3 1 0 → 3x + 1
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [3x² - 11x - 4]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 3 in your quotient can be a 3x, and the 1 follows right behind it, giving you the quotient of
.
I am joyous to assist you anytime.
The request is to find the intersection of the two sets. By definition, the intersection of two sets is another set, composed by all the elements appearing in both sets.
In other words,
is the set of all elements that P and Q have in common.
P contains all the numbers from 0 to 9, V contains all the odd numbers between 1 and 19. So, their intersection will be the odd numbers between 0 and 9, i.e.
![P\cap Q=\{1, 3, 5, 7, 9\}](https://tex.z-dn.net/?f=P%5Ccap%20Q%3D%5C%7B1%2C%203%2C%205%2C%207%2C%209%5C%7D)
Answer:
The standard deviation for incomes of civil engineers from the University of Montana is abnormally low.
and
The interquartile range and the standard deviation for incomes of civil engineers from the University of Montana are equal.