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Phantasy [73]
3 years ago
15

Which of the following supported a just peace?

Mathematics
2 answers:
mamaluj [8]3 years ago
8 0

Answer:

D

Step-by-step explanation:

United States

Vaselesa [24]3 years ago
3 0

Answer:

France

Hope This Helps!  Have A Nice Day!!

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use any strategy to solve the following problems 1) for haloween ned received 48 pieces of candy .if he put them into piles with
Veronika [31]

Answer:

He could make 16 piles.

Step-by-step explanation:

Divide 48 by 3: 48 ÷ 3 = 16

6 0
3 years ago
Need help asap in delta math assignment
V125BC [204]

Answer:

8

Step-by-step explanation:

B^2 = C^2 -A^2 89-25 = 64 sqrt(64) is 8

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3 years ago
Read 2 more answers
The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re
Zolol [24]

Answer:

a) df=n-1=16-1=15

The statistic calculated is given by t=3.3  

Since is a one-side upper test the p value would be:      

p_v =P(t_{15}>3.3)=0.0024  

So since the p value is lower than the significance level pv we reject the null hypothesis.

b) df=n-1=8-1=7

The statistic calculated is given by t=1.8  

Since is a one-side upper test the p value would be:      

p_v =P(t_{7}>1.8)=0.057  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

c) df=n-1=26-1=25

The statistic calculated is given by t=-0.6  

Since is a one-side upper test the p value would be:      

p_v =P(t_{25}>-0.6)=0.723  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation      

\bar X represent the sample mean

s represent the standard deviation for the sample

n sample size      

\mu_o =20 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:      

Null hypothesis:\mu \leq 20      

Alternative hypothesis:\mu > 20      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:  

df=n-1=16-1=15

The statistic calculated is given by t=3.3  

Since is a one-side upper test the p value would be:      

p_v =P(t_{15}>3.3)=0.0024  

So since the p value is lower than the significance level pv we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:  

df=n-1=8-1=7

The statistic calculated is given by t=1.8  

Since is a one-side upper test the p value would be:      

p_v =P(t_{7}>1.8)=0.057  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

 First we need to calculate the degrees of freedom given by:  

df=n-1=26-1=25

The statistic calculated is given by t=-0.6  

Since is a one-side upper test the p value would be:      

p_v =P(t_{25}>-0.6)=0.723  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

3 0
4 years ago
Find the range of possible values for the following measurements, which were rounded to the nearest mm, tenth of m, and hundredt
zmey [24]

The required range of the data is 24mm

The range of data is the difference between the largest value and the least value in a set of data.

Since we are not given the range of data. Let's assume we gave the following data:

34mm, 30mm, 20mm, 44mm, 31mm

From the data

Highest measurement = 44mm

Least measurement = 20mm

Find the range

Range = Highest measurement - Least measurement

Range = 44mm - 20mm

Range = 24mm

Hence the required range of data is 24mm

<em>NB: The concept can be applied to any set of data given for other measurements in (b) and (c)</em>

<em>Learn more here: brainly.com/question/1786006</em>

6 0
3 years ago
How do you multiply these polynomials?<br><br> 3xy^2(2y+4z)
nikitadnepr [17]

Answer:

6xy^3 +12xy^2 z

Step-by-step explanation:

3xy^2 (2y+4z)

Multiply

3xy^2 * 2y + 3xy^2 *4z

common factors

3xy^3 +3xy^2 *4z

Multiply

6xy^3 +12xy^2 z

7 0
3 years ago
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