First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
Answer:
1. mean=1.5, median=1.7, mode is 1.8
2. mean=102,median=134, mode=no mode
3. mean=1885,median=2300, mode=2300
Step-by-step explanation:
1. You have that:
- The trapezoids are similar.
- The larger base of the smaller trapezoid is 18 m and its area is 310 m².
- The larger base of the larger trapezoid is 32 m.
2. Then:
Sides=18/32
Sides=9/16
Area=(9/16)²
Area=81/256
3. Now, you can find the area of the larger trapezoid, as below:
81/256=310/x
81x=(310)(256)
x=79360/81
x=980 m²
Therefore, the answer is: The area of the larger trapezoid is 980 m².
<span>y^2 + 5y + 6
=</span><span>(y + 2)(y + 3)
----------------------------------</span>
y = 2 + x^6
y - 2 = x^6
x = (y - 2)^1/6
Well, solving this integral
= 2,69279
