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4 years ago

If x uniform distribution over (-5,9) find p(x>3)

Mathematics

1 answer:

Lena [83]4 years ago

8 0

$X$ has PDF

$f_X(x)=\begin{cases}\dfrac1{14}&\text{for }-5$

so that

$P(X>3)=\displaystyle\int_3^\infty f_X(x)\,\mathrm dx=\frac1{14}\int_3^9\mathrm dx=\frac37$

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3 years ago

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3 years ago

Half the sum of X and Y decreased by 1/3 why

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3 years ago

Calculator

Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24$

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4 years ago

HELP PLEASE!!!!!!!!!!!!

miskamm [114]

Given that < 1 and < 3 are corresponding angles with the same measure, and that < 1 and m < 38 ° are supplementary angles in which their measures add up to 180°:

Then:

m< 1 + m < 38° = 180°

m < 1 = 180° — m < 38°

m < 1 = 142°

Since m < 1 = m < 3, then m < 3 = 142°

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3 years ago

If x uniform distribution over (-5,9) find p(x>3) ​

If x uniform distribution over (-5,9) find p(x>3)