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nydimaria [60]
4 years ago
7

Can you gift points in this if yes please send some

Engineering
2 answers:
dimaraw [331]4 years ago
4 0
No, you can’t sorry :(
photoshop1234 [79]4 years ago
3 0

Answer:

no

Explanation:

why.

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What is the De Broglie wavelength of an electron under 150 V acceleration?
yanalaym [24]

Answer:

0.1 nm

Explanation

Potential deference of the electron is given as V =150 V

Mass of electron m=9.1\times 10^{-31}

Let the velocity of electron = v

Charge on the electron =1.6\times 10^{-19}C

plank's constant h =6.67\times 10^{-34}

According to energy conservation eV =\frac{1}{2}mv^2

v=\sqrt{\frac{2eV}{M}}=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 150}{9.1\times 10^{-31}}}=7.2627\times 10^{-6}m/sec

Now we know that De Broglie wavelength \lambda =\frac{h}{mv}=\frac{6.67\times 10^{-34}}{9.1\times 10^{-31}\times 7.2627\times10^6 }=0.100\times 10^{-9}m=0.1nm

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3 years ago
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Mnenie [13.5K]

Answer:Just multiply 90 by itself 46 times

Explanation:

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4 years ago
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Knowing that v = –8 m/s when t = 0 and v = 8 m/s when t = 2 s, determine the constant k. (Round the final answer to the nearest
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Answer:

a)We know that acceleration a=dv/dt

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dv=kt^2dt

Integrating we get

v(t)=kt^3/3+C

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8=8k/3-8

k=48/8

k=6

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3 years ago
Briggs & Stratton engines feature both a pressure lubrication and a pressure filtration system. Which statement is true?
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