Answer:
load factor = 0.782
Shrink Factor = 0.833
no of truck is 62500
Explanation:
given data
soil weighs in situ condition = 2,520 lbs/CY
soil weighs in loose condition = 1,970 lb/CY
soil weighs in embanked state = 3,025 lbs/CY
average volume = 16 LCY
soil from a borrow pit = 1 million CCY
solution
first we get here Load Factor that is express as
load factor =
load factor = 0.782
and Shrink Factor will be as
Shrink Factor =
Shrink Factor = 0.833
and
no of truck will be
no of truck =
no of truck is 62500
Answer:
<em><u>The 'shoulder' of a road is the land to the edge of the road. On most roads without pavements, the shoulder is a strip of grass or a hedgerow. This is known as a 'soft shoulder'. On a motorway, this strip of land is hardstanding, hence the name 'hard shoulder.'</u></em>
<em><u>Mark</u></em><em><u> </u></em><em><u>as</u></em><em><u> brilliant</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u> </u></em>
Answer:
the required diameter is 0.344 m
Explanation:
given data:
flow is laminar
flow of carbon dioxide Q = 0.005 Kg/s
for flow to be laminar, Reynold's number must be less than 2300 for pipe flow and it is given as

arrange above equation for diameter
\frac{\rho Q D}{\mu A }<2300
dynamic density of carbon dioxide = 1.47×
Pa sec
density of carbon dioxide is 1.83 kg/m³


D = 0.344 m
Answer: what is the formula
Explanation:
I can’t figure nothing out with out the formula
Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.