No se ve la foto :( puedes a ser la pregunta otra ves?
Answer:
Technician A is wrong
Technician B is right
Explanation:
voltage drop of 0.8 volts on the starter ground circuit is not within specifications. Voltage drop should be within the range of 0.2 V to 0.6 V but not more than that.
A spun bearing can seize itself around the crankshaft journal causing it not to move. As the car ignition system is turned on, the stater may draw high current in order to counter this seizure.
Answer:
N=945.76 RPM
Explanation:
Given that
A= 0.15 m
Acceleration = 0.6 g
a=0.6 x 9.81 m/s²
a= 5.886 m/s²
We know that acceleration a given as
a = ω² A
ω=Angular speed

ω=99.04 rad/s
We know that


N=945.76 RPM
Therefore the speed of the motor will be 945.76 RPM.
Answer:
Technician A only
Explanation:
Rapid wear of the sealing ring and the seal ring groove are result of excessive end play