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agasfer [191]
3 years ago
13

A steel ship deck plate is 30 mm thick and 12 m wide. It is loaded with a nominal uni- axial tensile stress of 70 MPa. It is ope

rated below its ductile-to-brittle transition temperature with KIc equal to 38.3 MPa. If a 65-mm-long central transverse crack is present, estimate the tensile stress at which catastrophic failure will occur. Compare this stress with the yield strength of 240 MPa for this steel.

Engineering
1 answer:
MAXImum [283]3 years ago
7 0

Answer:

The answer is given in the attachments

Explanation:

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Answer:

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Explanation:

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What does the General Duty Clause require employers to do?
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Meggers are used to measure ​
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Consider a power plant with a heat rate of 10,800 kJ/kWh burning bituminous coal with 75 percent carbon and a heating value (ene
grandymaker [24]

Answer:

1. \eta_{p} = 33.34%

2. m_{coal} = 0.396 kg/kWh

3. carbon emission = 0.297 kg/kWh[/tex]

4. carbon-dioxide emission = 1.089 kg/kWh

5. Min flow of cooling water =  = 1457.14 kg/kWh

Given:

Heat Rate = 10,800 kJ/kWh

Heating value = 27,300 kJ/kg

Solution:

In order to calculate the plant efficiency, [rex]\eta_{p}[/tex]

Heat rate in coal fired steam power plant = \frac{3600}{\eta_{p}}

Therefore,

\eta_{p} = \frac{3600}{Heat rate}

\eta_{p} = \frac{3600}{10800}\times 100 = 33.34%

Now,

To calculate mass of coal per kWh, m_{coal}:

m_{coal} = \frac{Required heat rate}{heating value per kg}

m_{coal} = \frac{10800}{27300} = 0.396 kg/kWh

Now,

Rate of emission carbon and carbon-dioxide from the plant:

In accordance to the question, 75% of the bituminous coal being burned is carbon, thus carbon emission is given by:

carbon emission = 0.75\times m_{coal}

carbon emission = 0.75\times 0.396 = 0.297 kg/kWh = 29.7%

Now, for carbon-dioxide emission:

Since, molecular weight of carbon-dioxide = 44 kg

Thus carbon-dioxide emission:

0.297\times \frac{44}{12} = 1.089 kg/kWh

The minimum flow of cooling water per kWh if the allowance in temperature is 10^{\circ}:

\frac{0.85\times \frac{2}{3}\times 10800}{4.2} = 1457.14 kg/kWh

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Answer:

<em><u>note:</u></em>

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