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otez555 [7]
4 years ago
10

Two transmission belts pass over a double-sheaved pulley that is attached to an axle supported by bearings at A and D. The radiu

s of the inner sheave is 125 mm and the radius of the outer sheave is 250 mm. Knowing that when the system is at rest, the tension is 100 N in both portions of belt B and 160 N in both portions of belt C, determine the reactions at A and D. Assume that the bearing at D does not exert any axial thrust.

Engineering
1 answer:
Fynjy0 [20]4 years ago
6 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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The entrance of the space module into atmosphere is one of the very critical phases of any space mission. Due to the formation o
Hatshy [7]

Answer:

Check the explanation

Explanation:

The transferred energy calculations can be done using the equation:

This is when:

• power is calculated in watts (W)

• energy is calculated in joules (J)

• time is calculated in seconds (s)

it can also be calculated by utilizing the same equation but with different units:

• when energy is measured in kilowatt-hours (kWh)

• when power is measured in kilowatts (kW)

• and when time is measured in hours (h)

kindly check the comprehensive step by step calculation to the question in the attached images below

5 0
4 years ago
Administrative controls can be broken down into two categories; programs such as
Anastaziya [24]

Administrative controls can be broken down into two categories; programs such as  HAZCOM and activities such as housekeeping is a TRUE statement.

Explanation:

  • Administrative controls (or work practice controls) are changes in work procedures such as written safety policies, rules, supervision, schedules, and training with the goal of reducing the duration, frequency, and severity of exposure to hazardous chemicals or situations.
  • Some common examples of administrative controls include work practice controls such as prohibiting mouth pipetting and recapping of needles, as well as rotating worker shifts in coal mines to prevent hearing loss.
  • Administrative controls are fourth in larger hierarchy of hazard controls, which ranks the effectiveness and efficiency of hazard controls.
  • The two categories of administrative controls programs and activities.

3 0
4 years ago
A 100-horsepower, three-phase squirrel-cage induction motor is connected to a 240-volt line. A dual-element time-delay fuse is t
antoniya [11.8K]

Based on the National Electrical Code (NEC), a 450-Ampere fuse should be used to protect this polyphase (three-phase) squirrel cage inductor motor.

<u>Given the following data:</u>

  • Power rating = 100-horsepower.
  • Voltage = 240 volt.

<h3>How to determine the correct fuse rating?</h3>

According to Table 430.52 of the National Electrical Code (NEC), a dual-element time delay fuse should be calculated at 175% (1.75) of the full-load current rating for an alternating current (AC) polyphase (three-phase) squirrel cage inductor motor.

In this scenario, the squirrel cage inductor motor didn't list a NEMA design code on its nameplate. Thus, we'll assume that the inductor motor is design B and its fuse rating is given by:

Fuse rating = 248 × 1.75 × 434

In conclusion, the nearest standard fuse size which is above the computed value listed in Section 240.6 of the National Electrical Code (NEC) is 450 amperes.

Read more on National Electrical Code here: brainly.com/question/10619436

#SPJ1

6 0
2 years ago
Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5160 kJ/h for each kW of power it c
Mars2501 [29]

Answer:

COP_R=1.433\\Q_H=2.433kW

Explanation:

Hello,

In this case, the coefficient of performance of this refrigerator is defined in terms of the removed heat and the work input as:

COP_R=\frac{Q_{L}}{W_{in}} =\frac{5160\frac{kJ}{h}*\frac{1h}{3600s} }{1kJ/s} =1.433

Moreover, the rate of heat rejection to the outside air tuns out:

W_{in}=Q_H-Q_L\\Q_H=W_{in}+Q_L=1kW+5160\frac{kJ}{h}*\frac{1h}{3600s} =2.433kW

Best regards.

3 0
3 years ago
Read 2 more answers
Illinois furniture , Inc produces all types of coffee furniture the executive secretary is a chair that has been designed using
o-na [289]

This question is incomplete, the complete question is;

Illinois furniture , Inc produces all types of office furniture. The "Executive Secretary" is a chair that has been designed using ergonomics to provide comfort during long work hours the chair sells for $130. There are 480 minutes available during the day and the average daily demand has been 50 chairs. There are eight tasks.

TASK     PERFORMANCE TIME( MIN )     TASK MUST FOLLOW TASK LISTED

A                            4                                                     ---------

B                            7                                                     ----------

C                            6                                                        A,B

D                            5                                                          C

E                            6                                                          D

F                            7                                                           E

G                            8                                                          E

H                            8                                                          F,G

1) What is the cycle time for operation?

2) What is the theoretical minimum number of workstation?

Answer:

1) the cycle time for operation is 9.6 min

2) the theoretical minimum number of workstation is 5

Explanation:

Given the data in the question;

production time per day = 480 minutes

average daily demand = 50

Given the data in the question;

1) cycle time for operation

this is simply referred to as the total time for the process from start to finish.

cycle time = production time per day / units demand per day

we substitute

cycle time = 480 min / 50

cycle time = 9.6 min

Therefore, the cycle time for operation is 9.6 min

2) theoretical minimum number of workstation.

theoretical minimum number of workstation = total task time / cycle time

Total task time = ( 4 + 7 + 6 + 5 + 6 + 7 + 8 + 6 ) = 49 min

∴  theoretical minimum number of workstation = 49 min / 9.6 min

theoretical minimum number of workstation = 5.104 ≈ 5

Therefore, the theoretical minimum number of workstation is 5

7 0
4 years ago
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