Answer:
He messed up the signs, most likely by multiplying incorrectly. It should be 53x+12.
Step-by-step explanation:
You begin by multiplying both -2 and -10x by -6.
Remember a negative times a negative makes a positive.
-6(-2-10x)
12+60x
Then you need to combine like terms which are 60x and -7x
60x-7x
53x
So that means the final answer will be
53x+12
Answer:
a) Эx ∈ R ⊇ x³ = 2
b) ∀x ∈ R, x² ≥ 0
c) Эx ∈ R ⊇ x³ = x
d) ∀x ∈ R, x ≤ x²
Step-by-step explanation:
Given the data in the question;
let us first go through some symbols and their possible meanings;
Э ⇒ there exists
∀ ⇒ for all
∈ ⇒ belongs to or set membership or element of the set
⊇ ⇒ such that
now;
a) There is a number whose cube is equal to 2
let x represent the number; so
Эx ∈ R ⊇ x³ = 2
b) The square of every number is at least 0
x² ≥ 0, ∀x ∈ R
∀x ∈ R, x² ≥ 0
c) There is a number that is equal to its square
Эx ∈ R ⊇ x³ = x
d) Every number is less than or equal to its square.
x ≤ x², ∀x ∈ R
∀x ∈ R, x ≤ x²
C(0,4)
B to C is (+1,+4)
so A to D is also (+1,+4)
