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2 years ago

How do i write this in standard form? (12-11x-5x^5)-(4x^4+8x-4x^5+2x^3-1)

Mathematics

1 answer:

algol132 years ago

5 0

8x+4x+2x=14x
12×5×3-1=-14

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Daniel reads dor 8 times as many as April. Daniel read 44 minutes this week. How many minutes does April read?

ELEN [110]

44 [minutes] * 8 [times as many as April] = 352 [minutes in April]

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2 years ago

Which of the following coordinate points have a y-value of 1? Select all that apply.

Nimfa-mama [501]

Answer:

B is the right answer,...B) (6, 1)

Step-by-step explanation:

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2 years ago

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Taylor has 16 tacks. she buys 2 packages of 36 tacks. how many gate sale posters can she put up if she uses 4 tacks for each pos

Gemiola [76]

She can Hang up 4 posters. Because Taylor only has 16 tacks.

16/4=4

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3 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago

Suppose f(x) =6x second power-4, what is f(-1)?

meriva

Answer:

f(-1)=6×(-1)^-4=6/(-1)^4=6/1=6

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3 years ago

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