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3 years ago

A. (100 - 25pie sign) sq in.

Mathematics

2 answers:

mars1129 [50]3 years ago

6 0

Its D. 87.5 pie sign sq in.

morpeh [17]3 years ago

3 0

The 4 querter circles make one whole circle so their area = pi 5^2 = 25 pi
The area of the square = 10*10 = 100

So area of shaded part = (100 - 25pi) sq in.

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If a jogger jogs 6 kilometers in 45 minutes what is his speed

kaheart [24]

45 minutes = 3/4 hours

so his speed = 6 / 3/4 kph

= 8 km / h Answer

6 0

3 years ago

Lines g and h are parallel and m 2 = 118°.

irina [24]

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7 0

4 years ago

A company finds it can produce 15 heaters for $ 4050â€‹, while producing 25 heaters costs $ 6550. Express theâ€‹ cost, y, as a l

amid [387]

Answer:

y=250x+300

Step-by-step explanation:

Let x be the number of heaters and y be the total cost.

We need to find the linear function for y in terms of x.

It is given that company can produce 15 heaters for $4050 and 25 heaters costs $ 6550.

It means the line passes through the points (15,4050) and (25,6550).

If a line passes through two points $(x_1,y_1)$ and $(x_2,y_2)$ , then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The equation of line is

$y-4050=\frac{6550-4050}{25-15}(x-15)$

$y-4050=\frac{2500}{10}(x-15)$

$y-4050=250(x-15)$

$y-4050=250x-3750$

Add 4050 on both sides.

$y-4050+4050=250x-3750+4050$

$y=250x+300$

Therefore, the required linear function is y=250x+300.

8 0

3 years ago

Let f be a differentiable function such that f(1)=π and f'(x)=√x^3+6. what is the value of f(5)?

natali 33 [55]

The value of f(5) is 49.1

Step-by-step explanation:

To find f(x) from f'(x) use the integration

f(x) = ∫ f'(x)

1. Find The integration of f'(x) with the constant term

2. Substitute x by 1 and f(x) by π to find the constant term

3. Write the differential function f(x) and substitute x by 5 to find f(5)

∵ f'(x) = $\sqrt{x^{3}}$ + 6

- Change the root to fraction power

∵ $\sqrt{x^{3}}$ = $x^{\frac{3}{2}}$

∴ f'(x) = $x^{\frac{3}{2}}$ + 6

∴ f(x) = ∫ $x^{\frac{3}{2}}$ + 6

- In integration add the power by 1 and divide the coefficient by the

new power and insert x with the constant term

∴ f(x) = $\frac{x^{\frac{5}{2}}}{\frac{5}{2}}$ + 6x + c

- c is the constant of integration

∵ $\frac{x^{\frac{5}{2}}}{\frac{5}{2}}=\frac{2}{5}x^{\frac{5}{2}}$

∴ f(x) = $\frac{2}{5}$ $x^{\frac{5}{2}}$ + 6x + c

- To find c substitute x by 1 and f(x) by π

∴ π = $\frac{2}{5}$ $(1)^{\frac{5}{2}}$ + 6(1) + c

∴ π = $\frac{2}{5}$ + 6 + c

∴ π = 6.4 + c

- Subtract 6.4 from both sides

∴ c = - 3.2584

∴ f(x) = $\frac{2}{5}$ $x^{\frac{5}{2}}$ + 6x - 3.2584

To find f(5) Substitute x by 5

∵ x = 5

∴ f(5) = $\frac{2}{5}$ $(5)^{\frac{5}{2}}$ + 6(5) - 3.2584

∴ f(5) = 49.1

The value of f(5) is 49.1

Learn more:

You can learn more about differentiation in brainly.com/question/4279146

#LearnwithBrainly

4 0

3 years ago

The vertex of this parabola is at (3,5) when the y-value is 6 the x value -1 what is the coefficient of the squared term in the

ale4655 [162]

Answer:

1/16

Step-by-step explanation:

Here,

Vertex =(3,5)

x= -1, y=6

Simply,eqn of parabola is given by ax^2+bx+c=y

So, coefficient of squared term (x^2) is 'a'

Therefore, we've to find the value of a

Moving on to solution:

a-b+c=6 ___(i) (by putting the given values of x and y in eqn of parabola )

We know that,

Vetex=(-b/2a, ( 4ac-b^2)/4a)

(3,5) = (-b/2a , (4ac-b^2)/4a)

Equating corresponding sides,we get

3= -b/2a

b=-6a___(ii)

Again,

5=(4ac-b^2)/4a

5=(4ac/4a) - (b^2/4a)

5= c- (36a^2/4a) (by putting value of b from eqn ii )

5= c-9a___(iii)

Now,moving back to the first eqn

a+6a+5+9a=6

16a=1

therefore,a=1/16

Hence ,the required value of coefficient of squared term is 1/16.

I tried my best to give clear explanation as much as I know. It's just we've have to find the value of a . For that, you can use any method you find easier.

3 0

3 years ago