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Natalija [7]
3 years ago
5

The volume of a sphere is 32 3 π cubic centimeters. What is the radius? Sphere V = 4 3 πr3

Mathematics
2 answers:
allsm [11]3 years ago
4 0

Answer:

To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.

V=43(π)(r3)

In this equation, r is equal to the radius. We can plug the given radius from the question into the equation for r.

V=43(π)(123)

Now we simply solve for V.

V=43(π)(1728)

V=(π)(2304)=2304π

Answer is 2304

m_a_m_a [10]3 years ago
4 0

Answer:

2

Step-by-step explanation:

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The equation of the line that goes through points (1,1) and (3,7) is \mathbf{y=3x-2}

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Determine the equation of the line that goes through points (1,1) and (3,7)

We can write the equation of line in slope-intercept form y=mx+b where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=1, y_1=1, x_2=3, y_2=7

Putting values and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{7-1}{3-1}\\Slope=\frac{6}{2}\\Slope=3

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Finding y-intercept

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y=mx+b\\1=3(1)+b\\1=3+b\\b=1-3\\b=-2

We get y-intercept b = -2

So, equation of line having slope m=3 and y-intercept b = -2 is:

y=mx+b\\y=3x-2

The equation of the line that goes through points (1,1) and (3,7) is \mathbf{y=3x-2}

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geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

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L_\lambda=x-y+z-1=0

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