The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
Answer:
3/2
Step-by-step explanation:
Answer:
because it may not be suitable for all the time
Answer:
angle 3 = 79 degree
Step-by-step explanation:
given:
angle 1 = 98 degree
angle 2 : 19 degree
angle 3 =?
angle 2 + angle 3 =angle 1 (sum of two interior angle opposite angles is equal to the exterior angle formed)
19 + angle 3 = 98
angle 3 = 98 - 19
angle 3 = 79 degree
$90+25x=240
240-90
150/25
The answer is C.6
