Answer:
range you can calculate maximum value - minimum value 78- 46=32
The correct answer is option C which is 230p – 1010 = 650p – 400 – p this expression is same as of 2.3p – 10.1 = 6.5p – 4 – 0.01p.
<h3>What is an expression?</h3>
Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Given expression:-
2.3p – 10.1 = 6.5p – 4 – 0.01p
The same expression will be calculated as:-
Multiply the given expression by 100 we will get our answer.
E = 100 (s 2.3p – 10.1 = 6.5p – 4 – 0.01p )
E = 230p – 1010 = 650p – 400 – p
Therefore the correct answer is option C which is 230p – 1010 = 650p – 400 – p this expression is same as of 2.3p – 10.1 = 6.5p – 4 – 0.01p.
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Answer:
Step-by-step explanation:
a₆ = a₁r⁶⁻¹ = (-2)4⁵ = -2048
Solution:
Vertices of Triangle = O(0,0), A(1,0) and B(0,1).
Dilation Centered at (1,0) is applied to the triangle.
It means vertices of triangle has moved 1 unit horizontally right and there will be no change in vertices of y.
So, New Vertices of Triangle = O'(1,0), A'(2,0), C(1,1)
As you can see sides joining (0,0) and (1,0) i.e preimage And sides joining (1,0) and (2,0) i.e image lie on the same line i.e on X axis.
So, the correct option is one of the sides lie on the same line as their respective images.
Given Information:
Mean salary of employees = μ = $5000
Standard deviation = σ = $500
Sample size = n = 40
Required Information:
P(X < $4900) = ?
Answer:
P(X < $4900) = 0.102 = 10.2%
Step-by-step explanation:
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
Let X is the random variable that represents the salary of employees at company.
![P(X < \$ 4900) = P(Z < \frac{x - \mu}{\frac{\sigma}{\sqrt{n} } } )\\\\P(X < \$4900) = P(Z < \frac{4900 - 5000}{\frac{500}{\sqrt{40} } } )\\\\P(X < \$4900) = P(Z < \frac{4900 - 5000}{79} )\\\\P(X < \$4900) = P(Z < \frac{-100}{79} )\\\\P(X < \$4900) = P(Z < -1.27)\\](https://tex.z-dn.net/?f=P%28X%20%3C%20%5C%24%204900%29%20%3D%20P%28Z%20%3C%20%5Cfrac%7Bx%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20%29%5C%5C%5C%5CP%28X%20%3C%20%5C%244900%29%20%3D%20P%28Z%20%3C%20%5Cfrac%7B4900%20-%205000%7D%7B%5Cfrac%7B500%7D%7B%5Csqrt%7B40%7D%20%7D%20%7D%20%29%5C%5C%5C%5CP%28X%20%3C%20%5C%244900%29%20%3D%20P%28Z%20%3C%20%5Cfrac%7B4900%20-%205000%7D%7B79%7D%20%29%5C%5C%5C%5CP%28X%20%3C%20%5C%244900%29%20%3D%20P%28Z%20%3C%20%5Cfrac%7B-100%7D%7B79%7D%20%29%5C%5C%5C%5CP%28X%20%3C%20%5C%244900%29%20%3D%20P%28Z%20%3C%20-1.27%29%5C%5C)
The z-score corresponding to -1.27 from the z-table is 0.102
![P(X < \$4900) = 0.102\\P(X < \$4900) = 10.2 \%](https://tex.z-dn.net/?f=P%28X%20%3C%20%5C%244900%29%20%3D%200.102%5C%5CP%28X%20%3C%20%5C%244900%29%20%3D%2010.2%20%5C%25)
Therefore, there is 10.2% probability that the salary of a randomly selected employee will be less than $4900.
How to use z-table?
Step 1:
In the z-table, find the two-digit number on the left side corresponding to your z-score.(e.g -1.2, 2.2, etc.)
Step 2:
Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 1.27 then go for 0.07 column)
Step 3:
Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.